Lia=L
Phil=12.80+L
Cam=3L
L+12.80+L+3L=200.30
5L+12.80=200.30
5L=200.30-12.80
5L=187.5
L=187.5/5
Plug into the equations at the top
L=Lia=$37.5
Phil=12.80+37.5=$50.30
Cam=3(37.5)=$112.50
Answer:
Answer: Sample Response: The height of the triangle will be twice the height of the rectangle. The area of a triangle is ½ bh and the area of a rectangle is bh. If the bases are the same, then the height of the triangle has to be double that of the rectangle in order to get the same area.
Step-by-step explanation:
1. so since we assume that CF is a straight line that means that the angle CAF is 180 angle CAD is 90 and FAE is 65 so 180-(65+90)=DAE=25
2. so since angle QPR= angle TPS (both are signified by f) and we assume that QT is straight so then QPT=180
180-154=2f=26
angle f=13
QPR=13
3. so we assume that BG is straight so it is 180
we add up the known angles (BQD+DQE+FQG=10+103+12=125) 180-125=DQC+EQF=55=2x+3x=5x
5x=55
x=11
CQD=2x=22
EQF=3x=33
4. we know that x=x and the whole is 360 so
x+x+x+x+71+71+71+71=360=4x+284=360
4x=76
x=19
8. so we assume that EF and CD are straight lines so EQD=CQF so 155=56+3x so
99=3x
CQG=99
9. so adjacent and the ratio is 4:5 so a line is 180 so 4+5=9 180/9=20 20*4=80 20*5=100 4:5 =80:100
a. 80 and 100
b. you should be able to do this
10. so on a line is 180
a. 3:4:5 3+4+5=12 180/12=15
3*15=45 4*15=60 5*15=75
3:4:5 =45:60:75
the angles are 45 60 75
b. you should be able to do this from my work
