Answer: The equation is y = -6*x
Step-by-step explanation:
I suppose that we want to find the equation for a line that passes through the point (-1, 6) and the origin (remember that the origin is the point (0,0))
A general linear equation is written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
If this line passes through the points (x₁, y₁) and (x₂, y₂), then the slope of the line is equal to:
a = (y₂ - y₁)/(x₂ - x₁)
Now we know that our line passes through the points (0, 0) and (-1, 6), then the slope is:
a = (6 - 0)/(-1 - 0) = 6/-1 = -6
Then our equation is something like:
y = -6*x + b
To find the value of b we can use the fact that this line passes through the point (0, 0).
This means that when x = 0, y is also equal to zero.
If we replace these values in the equation we get:
0 = -6*0 + b
0 = b
Then our equation is:
y = -6*x
The correct option is: Option (C) 2Explanation:The slope formula is = m =
Insert the values in the above formula:
m =
Which is Option (C).
Answer:
- 
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope (gradient) and c the y- intercept )
Given
2y = - 3x - 8 ( divide all terms by 2 )
y = - x - 4 ← in slope- intercept form
with gradient = -
114/2=57 I believe 57 is the correct answer
