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2 years ago

9

Complete each ordered pair so that it is a solution of the given linear equation. x - 3y=4;(.-3), (-11, ) The first ordered pair

is 0-3).

1 answer:

AURORKA [14]2 years ago

3 0

Answer:

Step-by-step explanation:

x - 3y = 4

x - 3(-3) = 4

x + 9 = 4

x = -5

(-5, -3)

-11 - 3y = 4

- 3y = 15

y = -5

(-11, -5)

I don't see how (0, -3) could be a solution to the equation.

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Please help me if you know how to do this!

lukranit [14]

Question 21

Let's complete the square

y = 3x^2 + 6x + 5

y-5 = 3x^2 + 6x

y - 5 = 3(x^2 + 2x)

y - 5 = 3(x^2 + 2x + 1 - 1)

y - 5 = 3(x^2+2x+1) - 3

y - 5 = 3(x+1)^2 - 3

y = 3(x+1)^2 - 3 + 5

y = 3(x+1)^2 + 2

Answer: Choice D

============================================

Question 22

Through trial and error you should find that choice D is the answer

Basically you plug in each of the given answer choices and see which results in a true statement.

For instance, with choice A we have

y < -4(x+1)^2 - 3

-7 < -4(0+1)^2 - 3

-7 < -7

which is false, so we eliminate choice A

Choice D is the answer because

y < -4(x+1)^2 - 3

-9 < -4(-2+1)^2 - 3

-9 < -7

which is true since -9 is to the left of -7 on the number line.

============================================

Question 25

Answer: Choice B

Explanation:

The quantity (x-4)^2 is always positive regardless of what you pick for x. This is because we are squaring the (x-4). Squaring a negative leads to a positive. Eg: (-4)^2 = 16

Adding on a positive to (x-4)^2 makes the result even more positive. Therefore (x-4)^2 + 1 > 0 is true for any real number x.

Visually this means all solutions of y > (x-4)^2 + 1 reside in quadrants 1 and 2, which are above the x axis.

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3 years ago

Solve log 4x + log 13 = 0. Round to the nearest thousandth if necessary. a.0.019 b. 52 c.3.25 d. 0.311 Mathematics

kumpel [21]

Log4 + logX + log13 = 0
logX = -log13 - log4
logX = -1.716
x= 10^[-1.716]
x= 0.019 A

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3 years ago

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3 years ago

Anyone know the area?

Elina [12.6K]

Answer: The area of the triangle is: " 8.5 cm² " ;

or, write as: " 8 $\frac{1}{2}$ cm² " .
_______________________________________________________
Explanation:
_________________________________________________________
The formula {"equation"} for the area of a triangle is:

A = ( $\frac{1}{2}$ ) * b * h ;

in which: A = area;
b = base;
h = [perpendicular] height;
___________________________________
{also, can be written as: " A = (b * h) / 2 " .}.
______________________________________
Solve for the area, "A" ; by plugging in the known values shown in the figure (image attached):
______________________________________
base, "b" = 13 cm ;
[perpendicular] height, "h" = 5 cm ;
______________________________________
A = (b * h) / 2 ;

= (13 cm * 5 cm) / 2 ;

= [ (13 * 5) cm²] / 2 ;

= 65 cm² / 2 ;

A = " 8.5 cm² " ; or, write as: " 8 $\frac{1}{2}$ cm² " .
_________________________________________________________
Answer: " 8.5 cm² " ; or, write as: " 8 $\frac{1}{2}$ cm² " .
_________________________________________________________
The area of the triangle is: " 8.5 cm² " ;

or, write as: " 8 $\frac{1}{2}$ cm² " .
_________________________________________________________

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3 years ago

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boyakko [2]

Hi,

$f(x)=\log(x)$ FALSE

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→ $f(x)=\log(x-2)$

$f(x)=\log(x+2)$ FALSE

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3 years ago

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