Question

PLEASE HELP BRAINLIEST

Answer 1

Answer:

$h=15.23 \:\mathrm{in^2}$

Step-by-step explanation:

The surface area of this cylinder consist of two circles and a 3D outer edge with respect to the circumference. The area of a circle is given as $r^2\pi$. Using $\pi=3.14$ as requested in the problem, the area of both these circles is:

$2\cdot6^2\cdot 3.14=226.08\:\mathrm{in^2}$.

The 3D outer edge is then $800-226.08=573.92\:\mathrm{in^2}$.

The area of this 3D outer edge is represented by $2r\pi\cdot h$. Therefore, we set up the following equation:

$2r\pi\cdot h=573.92, \\h=\frac{573.92}{2r\pi}, \\h=\fbox{ 15.23\:\mathrm{in^2} }$.