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MissTica
3 years ago
15

Some students reported how many pets they had. The dot plot shows the data collected: A dot plot is titled Students Pets and lab

eled Number of Pets. The values on the horizontal line are 0, 1, 2, 3, and 4. There are 5 dots above 0, 4 dots above 1, 3 dots above 2, 2 dot above 3, and 1 dot above 4. What do the dots above the number 3 indicate? (3 points)
A. There are exactly 2 students with 3 pets.

B. There are exactly 3 students with 2 pets.

C. There are exactly 2 students with more than 3 pets.

D.There are exactly 3 students with more than 2 pets.
Mathematics
2 answers:
Vilka [71]3 years ago
6 0

Answer:

d

Step-by-step explanation:

:)

77julia77 [94]3 years ago
5 0

Answer:

  • A. There are exactly 2 students with 3 pets.

Step-by-step explanation:

  • 5 dots above 0     ⇒ 5 students with no pets
  • 4 dots above 1      ⇒ 4 students with 1 pet
  • 3 dots above 2     ⇒ 3 students with 2 pets
  • 2 dot above 3       ⇒ 2 students with 3 pets
  • 1 dot above 4        ⇒ 1 student with 4 pets

Correct choice is A

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8^{4v}+5=31
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4v=log₈26
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if yo use calculator
go back
8^{4v}=26
take ln of both sides
4vln8=ln26
divide both sides by (4ln8)
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3 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
4 years ago
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kondaur [170]
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3 years ago
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Answer:

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Step-by-step explanation:

4 0
3 years ago
How do i solve for x
Vladimir79 [104]
Multiply both sides by 2 to clear the fraction.
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