Answer:
3 
Step-by-step explanation:
change 1 
to an improper fraction
1 = 
, thus
× = 
= 3 or 3.57 ( to 2 dec. places )
The acceleration is given by the slope of the line. This line passes through the points (0, 2) and (3, 5), so it has slope
which means the acceleration over this 3 second interval is 1 m/s^2.
Answer:
4cotα=tanα
4(1/tanα)=tanα
(4/tanα)=tanα
cross multiply
=> 4=tan²α
√4=√tan²α
±2=tanα
α=arc( tan) |2|
α=63.4° ( in first quadrant)
and
α=180+63.4=243.4 in the third quadrant
since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)
α=180–63.4=116.6° in the second quadrant
α=360–63.4=296.6 in the fourth quadrant
therefore theta( in my case, alpha) lies in all four quadrants and is equal to:
α=63.4°,243.4°,116.6°and 296.6°
Answer:
12.700 i think
Step-by-step explanation:
The correct answer is x=(300-p):20
