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likoan [24]
3 years ago
10

Tìm giá trị lớn nhất và giá trị nhỏ nhất của hàm số y=40

" id="TexFormula1" title="\sqrt{(x-1)x^{3 }" alt="\sqrt{(x-1)x^{3 }" align="absmiddle" class="latex-formula">- 3x-3
Mathematics
1 answer:
Doss [256]3 years ago
3 0

si 8888888888888888888888888888

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A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
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Answer:

The correct option is;

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Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

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Answer:

mary broke

Step-by-step explanation:

it simple she will need to pay 2338 apples

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I'm kind of thrown off for that negative sign, but I try it out in the one that makes sense is this one [ https://gyazo.com/192a76e70d2d46979691cabbf06e6c85 ] If you can better of explain where the negative sign will be great. Hope I helped. 
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