You are given a rectangle and are told that the length is 1 cm more than twice the width of the rectangle. The area of the rect. is also given, and is 21 cm^2.
Find the length and width. To do this, represent the length by y and the width by x. Then "1 cm more than twice the width" comes out to y=2x+1 (cm).
Since the area of a rect. is equal to the product of its length and width,
x(2x+1)=21 cm^2. Multiply out x(2x+1). show your work. Next, subtract 21 from both sides. Write your algebraic expression on the left side as a quadratic equation in standard form.
Solve this quadratic equation for x. Recall that x (in cm) will represent the width of the rect., and y=2x+1 (in cm) will repr. the length.
The answer in this question is broadcast. Refer to curriculum topic: 5.1.3 On Ethernet networks, the broadcast MAC address is 48 binary ones displayed as hexadecimal FF-FF-FF-FF-FF-FF. So the hexadecimal address FF-FF-FF-FF-FF-FF represents broadcast the MAC address. The broadcast MAC address is a 48 binary.
Answer:
y=1
Step-by-step explanation:
The answer is a because 3/5 equals 0.6
