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miss Akunina [59]

2 years ago

10

What is (-49(49 x 5982+3)^2

2 answers:

Grace [21]2 years ago

5 0

-4.2100761e+12 your welcome

Phoenix [80]2 years ago

5 0

Answer:

$- 49 \times (49 \times 5982 + 3) {}^{2} \\ = - 49 \times 85919920641 \\ = - 4,210,076,111,409$

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Determine weather either of the points (-1,-5) and (0,-2) is a solution to the given system of equation

Anika [276]

Only the first one works
y = 3(-1)-2 = -5
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4 0

3 years ago

5 ports Use absolute value to express the distance between -12 and -15 on the number line. |-12 - (-15) = -27

zloy xaker [14]

Answer:

$Distance = 3$

Step-by-step explanation:

Given

-12 and -15

Required

Solve the difference

The question you posted included the solution. However, the solution is incorrect;

The absolute difference is represented as:

$Difference = \vert a - b \vert$

In this case:

$a = -12$

$b = -15$

So, the distance is calculated as:

$Distance = |-12 - (-15)|$

Open bracket

$Distance = |-12 +15|$

$Distance = |3|$

$Distance = 3$

3 0

3 years ago

6. Evaluate the function at each specified value of the independent variable and simplify. (If an answer is undefined, enter UND

Darya [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

6a

$V(3) = 113.112$

6b

$V(\frac{3}{2}) = 14.139$

6c

$V(2r) = 33.514r^3$

7a

$h(5) = 0$

7b

$h(t) = -5.76$

7c

$h(x+5) = x(x+5)$

Step-by-step explanation:

Considering the question 6

The function given is $V(r) = \frac{4}{3} \pi r^3$

For V(3) we have

$V(3) = \frac{4}{3} \pi 3^3$

$V(3) = \frac{4}{3} * 3.142 * 3^3$

$V(3) = 113.112$

For $V(\frac{3}{2})$

$V(\frac{3}{2}) = \frac{4}{3} * \pi * (\frac{3}{2})^3$

$V(\frac{3}{2}) = \frac{4}{3} * 3.142 * (\frac{3}{2})^3$

$V(\frac{3}{2}) = 14.139$

For V(2r)

$V(2r) = \frac{4}{3} \pi (2r)^3$

$V(2r) = \frac{4}{3} * 3.142*8r^3$

$V(2r) = 33.514r^3$

Considering the question 7

The function given is $h(t) = t^2 - 5t$

For h(5)

$h(5) = 5^2 - 5(5)$

$h(5) = 0$

For h(1.8)

$h(t) = 1.8^2 - 5(1.8)$

$h(t) = -5.76$

For h(x+ 5)

$h(x+5) = (x+5)^2 - 5(x+5)$

$h(x+5) = x^2 + 25+10x-5x-25$

$h(x+5) = x(x+5)$

7 0

3 years ago