Answer:
c = 24.34
Step-by-step explanation:
Here, we can use the cosine rule
Generally, we have this as:
a^2 = b^2 + c^2 - 2bcCos A
12^2 = 14^2 + c^2 - 2(14)Cos 19
144 = 196 + c^2 - 26.5c
c^2 - 26.5c + 196-144 = 0
c^2 - 26.5c + 52 = 0
We can use the quadratic formula here
and that is;
{-(-26.5) ± √(-26.5)^2 -4(1)(52)}/2
(26.5 + 22.23)/2 or (26.5 - 22.23)/2
24.37 or 2.135
By approximation c = 24.34 will be correct
Answer:


And the best option would be:
D. (0.191 to 0.249)
Step-by-step explanation:
For this case we know that the mean is:

And the standard error is given by:

We want to construct a 68% confidence interval so then the significance level would be :
and
. The confidence interval is given by:

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

And replacing we got:


And the best option would be:
D. (0.191 to 0.249)
Answer:
It's in the screenshot hope it helpsss
Step-by-step explanation:
The answer to your question would be 2.
(please give thanks if i am correct)
Answer:
(12)(3)(-2)
Step-by-step explanation: