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denpristay [2]
3 years ago
8

Which scenario can be represented using the inequalities below? 1.25 < x < 1.5

Mathematics
2 answers:
Fiesta28 [93]3 years ago
7 0

Answer:

The answer is D

Step-by-step explanation:

xz_007 [3.2K]3 years ago
3 0

Answer:

d. The point value of a test item is more than 1.25 points and less than 1.5 points.

Step-by-step explanation:

Write the inequality for each scenarios, as follows:

a. defining x: container of milk cost. Data: x is at least $1.25 but less than $1.50. These mean that x >= $1.25 and x < $1.5, because $1.25 is included but $1.5 is not.

b. defining x: minutes spent on homework by the student. Data: x is at least 1.25 hours ( 1 hour 15 minutes) but no more than 1.5 hours (1 hour 30 minutes). These mean that x >= 1.25 h and x < 1.5 h, because 1.25 h is included but 1.5 h is not.

c. defining x: tip added to a restaurant bill. Data: x  is less than or equal to 1.25 (addition of 25% to the bill) or less than or equal to 1.5 (addition of 50% to the bill). In the first case x <= 1.25 and in the second one x <= 1.5

d. defining x: the point value of a test item. Data: x  is more than 1.25 points and less than 1.5 points. These mean that x > 1.25 and x < 1.5

In consequence, only the last scenario can be represented by the inequality 1.25 < x < 1.5.

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Answer:

<h2>8/9</h2>

Step-by-step explanation:

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Hope this helps!

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Find the area of a circle with a radius r of 6 feet. Round off your answer to one decimal point. Hunt: the formula for the area
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8 0
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The manufacturer of a smart watch claims that individuals who pay attention to how many steps they take per day will inadvertent
drek231 [11]

Answer:

Hello your question is incomplete attached below is the complete question

answer :  1596 ± 2.861 \sqrt{\frac{1580^2 }{20 } +\frac{2350^2 }{20 } } ------  ( A )

Step-by-step explanation:

I will use excel function to resolve this question

<u>Determine the 99% confidence of interval for the difference in mean  number of steps by all people</u>

∝ = 0.01

critical value ( t ) = 2.861  ( = TINV ( 0.01, 19 )

Given that :

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Margin of Error = t * \sqrt{\frac{S^2_{1} }{n_{1} } +\frac{s^2_{2} }{n_{2} } }

∴  99% confidence of interval

= 1596 ± 2.861 \sqrt{\frac{1580^2 }{20 } +\frac{2350^2 }{20 } } ------

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3 years ago
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