A clump of soft clay is thrown horizontally from 9.80 m above the ground with a speed of 20.0 m/s. Assume it sticks in place whe
n it hits the ground At what time will the clay hit the ground
1 answer:
Answer:
Explanation:
The time to hit the ground will be same as time taken to fall from the height of 9.8 m with initial vertical velocity of zero .
Considering vertical displacement
initial velocity u = 0
displacement s = 9.8 m
acceleration a = g = 9.8 m /s²
time t = ?
s = ut + 1/2 g t²
9.8 = 0 + .5 x 9.8 x t²
t² = 2
t = √2 = 1.4 s
You might be interested in
<span>potential energy! Because the rock has the ability to possible move! So :)</span>
Hi
Here is a chart to help you
Hoped This Helps
Answer:
True.
Explanation:
Defenintion of Muscular Endurance:
The ability of a muscle (or set of muscles) to perform a repeated action without tiring.
3rd one with the hand and sun
