Which image illustrates diffraction

Syncopation is when we "shift" the beat off of the strong or down beat.

BabaBlast [244]

Given what we know, the statement in this question can be considered as true, since Syncopation does in fact shift the beat off of regular rhythms.

<h3>What is Syncopation?</h3>

This is when regular beats are offset in order to disrupt the melody.
This is done purposefully.
It causes the listener a need to continue in order to hear the beat return to normal.

Therefore, given that Syncopation is defined as a shift or displacement in the rhythms or beats from something <em><u>strong and normal</u></em> to something that causes the listener to want the beat to go back to normal.

To learn more about Syncopation visit:

brainly.com/question/9974881?referrer=searchResults

3 0

3 years ago

A NASCAR driver weighing 75 kg enters a corner with a radius of 155 meters. If his acceleration is 100 m/s2. What is tangential

Ymorist [56]

The tangential velocity of the car is 124.5 m/s

Explanation:

The centripetal acceleration of an object in uniform circular motion is given by:

$a=\frac{v^2}{r}$

where

a is the acceleration

v is the tangential velocity

r is the radius of the circle

For the car in this problem, we have:

$a=100 m/s^2$ is the centripetal acceleration

r = 155 m is the radius of the turn

Solving for v, we find the tangential velocity of the car:

$v=\sqrt{ar}=\sqrt{(100)(155)}=124.5 m/s$

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

3 0

3 years ago

A traffic expert wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. He a

galben [10]

Answer:

<em>Speed s= 19</em>

<u>Explanation:</u>

Take note of the following parameters:

Speed= s,

Number of cars= N,

Number N of cars that can pass a given spot per minute=

N(s)=88s/16+16(s19)2

The principle of differentiation is here:

We let N(s) = N

N = 86s / (17 + 17((s/19)^2))

17N = 86s /(1 + s²/19²)

17N = 361* 86s /(361 + s²)

17N = 31046s /(361 + s²)

Next step;

Differentiate with respect to s

17N = 31046s /(361 + s²)

Remember the quotient rule [u/v]’ = (vu’ - uv’) / v²

Therefore,

u = 31046s =====> du/ds = u’ = 31046

v = (361 + s²) ====>dv/ds = v’ = 2s

17N = 31046s /(361 + s²)

17 dN/ds = ( 31046(361 + s²) - 31046s(2s) ) / (361 + s²)²

The maximum when dN/ds = 0

17 dN/ds = ( 31046(361 + s²) - 31046s(2s) ) / (361 + s²)²

17 * 0 = ( 31046(361 + s²) - 31046s(2s) ) / (361 + s²)²

( 31046(361 + s²) - 31046s(2s) ) = 0

31046 [ (361 + s²) - 2s² ] = 0

31046 (361 - s²) = 0

(361 - s²) = 0

(19 - s)(19 + s) = 0

either s = -19 or s = 19, but s > 0

s = 19

4 0

3 years ago

Can someone help me !!

Leona [35]

Answer:

You are right with the answer you have, I believe!

Yeet

Explanation:

7 0

3 years ago

A person walks first at a constant speed of 5.00 m.s-1

Soloha48 [4]

The average speed of the person over the entire trip is 3.75 m/s.

<h3>Average speed of the person</h3>

Average speed = total distance/total time

Average speed = (d + d)/(d/Va + d/Vb)

where;

d is the distance in a single trip
Va is speed from point A
Vb is the speed from point B

Average speed = (2Vavb)/(Va + Vb)

Average speed = (2 x 5 x 3)/(5 + 3)

Average speed = 3.75 m/s

Thus, the average speed of the person over the entire trip is 3.75 m/s.

Learn more about average speed here: brainly.com/question/6504879

#SPJ1

4 0

2 years ago