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Tasya [4]
3 years ago
10

Which image illustrates diffraction

Physics
1 answer:
deff fn [24]3 years ago
8 0
3rd one with the hand and sun
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The distance of an illuminated object from its light source is decreased to 1/3 while the luminous flux remains constant. Which
Nostrana [21]

Answer:

The illuninance being multiplied by 9

Explanation:

6 0
3 years ago
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archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken
mario62 [17]

Answer:

a =45 m/s2

t = 2 seconds

Explanation:

Hi, to answer this question we have to apply the next formula:

v^2 = u^2 +2 a d

Where:

v = final velocity = 90 m/s

u = initial velocity = 0 m/s (shots from rest)

a = acceleration (m/s2)

d = distance = 90m

90^2 = 0^2 + 2a(90)

Solving for a:

8,100= 180 a

8,100/180 = a

a = 45 m/s^2

For time:

v = u + at

90 = 0 + 45t

90/45=t

t =2 seconds

6 0
3 years ago
A solar system has the five planets shown below. The mass of each planet is proportion
slava [35]

Answer:

Planet C

Explanation:

The figure of the problem is missing: find it in attachment.

The magnitude of the gravitational force between two objects is given by the equation:

F=\frac{Gm_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

In this problem, we have four planets around planet X, and the mass of each planet is proportional to its size in the figure.

As we can see from the previous equation, the magnitude of the gravitational force is proportional to the mass of the planets: therefore, the planet with largest mass will exert the largest gravitational force on planet X.

From the figure, we see that planet C has the largest size, so the largest mass: therefore, planet C exerts the greatest gravitational force on planet X.

6 0
4 years ago
7Which of the following terms describes how glaciers move?
tatuchka [14]

Answer:

D is the answer  I think (0 w 0 )

Explanation:

7 0
4 years ago
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For this quiz, we shall return to the radio control car track that we visited briefly on the last quiz. The track is 10 meters l
Iteru [2.4K]

Answer:

v=1.54\,\,metres\,\,per\,\,second

Explanation:

The given equation is x=x_0+vt where x_0 denotes initial time in the stopwatch and x denotes the distance covered by car.

As the judge starts her watch at the instant the car passes the 2.0 meter mark  (x_0=2) and the judge reads 3.9 seconds on her stopwatch when the car passes the 8.0 meter mark.

Put x_0=2,\,,\,x=8\,,\,t=3.9 in equation x=x_0+vt

8=2+3.9t\\8-2=3.9t\\6=3.9v\\v=\frac{6}{3.9}\\ v=1.54\,\,metres\,\,per\,\,second

3 0
3 years ago
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