Can you help me please
1 answer:
You might be interested in
Answer:
<h3>The answer is 2.15 m/s²</h3>Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
where
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>2.15 m/s²</h3>Hope this helps you
Missing question in the text:
"A.What are the magnitude and direction of the electric field at the point in question?
"A.What are the magnitude and direction of the electric field at the point in question?
B.<span>What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?"</span>
<span>Solution:
A) A charge q </span>under an electric field of intensity E will experience a force F equal to:
In our problem we have and
, so we can find the magnitude of the electric field:
The charge is negative, therefore it moves against the direction of the field lines. If the force is pushing down the charge, then the electric field lines go upward.
B) The proton charge is equal to
Therefore, the magnitude of the force acting on the proton will be
And since the proton has positive charge, the verse of the force is the same as the verse of the field, so upward.