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Ivahew [28]
3 years ago
12

Stem a choice b choice c choice d choice

Mathematics
1 answer:
MissTica3 years ago
8 0
C is the answer for sure
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What number on the number line represents ground level?<br>0<br>-1<br>-2<br>-3<br>-4<br>-5<br>-6​
ki77a [65]

Answer:

0 represents ground level.

Step-by-step explanation:

0 on the number line represents ground level. Based on the photo, the 0 is in between the underground and the space above. The answer cannot be one of the negative numbers because those are all shown to be underground in the photo.

5 0
3 years ago
Find the GCF of the polynomial 3a3b3 + 9a2b + a2
jasenka [17]

Answer:

a^2.

Step-by-step explanation:

The greatest common factor  is a^2.  It cannot be 3ab or 3a^2b because b is not present in the last term (a^2). Similarly there is no 3 or multiple of 3 in a^2.

5 0
3 years ago
A project has a forecasted cash flow of $110 in year 1 and $121 in year 2. Risk free rate is 5%, the estimated risk premium on t
Crazy boy [7]

From the question we are told that:

Cash Flow:

Year 1= \$110

Year 2 = \$121

Risk free rate is r=5%

Risk premium  R=10\%

\beta = 0.7.

a)

Generally, the equation for Equity Return is mathematically given by

e=r+\beta*R

e=0.05+(0.7*0.10)

e=0.12

Therefore Present Value (PV) is

PV=\frac{110}{1+0.12}+\frac{121}{1+0.12^2}

b)

Generally, the equation for  certainty-equivalent cash flow is mathematically given by

CE=(1+r)\frac{Year}{1+e}

Therefore

For Certainty-equivalent cash flow Year One

CE__=(1+0.05)\frac{110}{1+0.12}

CE_1=103.125

For Certainty-equivalent cash flow Year Two

CE_2=(1+0.05)\frac{121}{1+0.12}

CE_2=113.4

c)

The Ratio of the certainty-equivalent cash flows to the expected cash flows in years 1 and 2 could be written as

R=103.125:113.4

or

R=\frac{103.125}{113.4}

7 0
3 years ago
PLEASE HELP!!!!! QUICK!! LOTS OF POINTSSSS!!!!!
brilliants [131]

Answer:

B

Step-by-step explanation:

I did That before

3 0
3 years ago
Read 2 more answers
I to the exponent of 65
larisa86 [58]

Answer:

Step-by-step explanation:

A= 1 * 1 = 2

A2 = 1 * (1 * 1)

A2 = 1 * 1

A2 = 1

a3 = 1 * 1 * (1 * 1)

a3 = 1 *1 * 1

a3 = 1 * (1*1)

a3 = 1* 1

a3 = 1

You keep on going in this manner until you hit 1^65 = 1

The only thing you have to accept is that (1 * 1) = 1

5 0
3 years ago
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