All categories

3 years ago

Paisley is going to invest in an account paying an interest rate

Mathematics

1 answer:

PolarNik [594]3 years ago

3 0

Answer:

She needs to do 23 sex a day and big pssyyyyyy

Step-by-step explanation:

uhhhhh

You might be interested in

1 Pound brown sugar is equivalent to _____ cups

iogann1982 [59]

Answer:

3 1/2 or said as 3.5 cups is equal to 1 pound

Step-by-step explanation:

1 Pound brown sugar is equivalent to ___3 1/2 or 3.5 __ cups

Hope This Helped

7 0

2 years ago

1. How many ways are there to make an octagon with 19 different sticks when order DOESN’T matter?

mart [117]

Answer:

1. 19C8 = 75582

2. 19P8= 3047466240

Step-by-step explanation:

First, find the number of ways to get 8 sticks from 19. At first, you have 19 choices, then 18, then 17, all the way to 12. Giving you 19*18*17*...*13*12, or 19!/11!.

Combination:

When order doesn't matter, you have to divide 19!/11! by the number of ways to order 8 sides, or 19!/11!/8!=19C8=75582

Permutation:

When order doesn't matter, you don't have to divide 19!/11! by the number of ways to order 8 sides, since you count each of these, and 19!/11!=19P8=3047466240.

6 0

3 years ago

A researcher surveyed 150 high school students and found that 68% played a musical insturment. What would be a reasonable range

maria [59]

Answer:

The reasonable range for the population mean is (61%, 75%).

Step-by-step explanation:

The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, $\hat p$ .

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 150

$\hat p$ = 0.68

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.68\pm1.96\sqrt{\frac{0.68(1-0.68)}{150}}\\\\=0.68\pm 0.0747\\\\=(0.6053, 0.7547)\\\\\approx (0.61, 0.75)$

Thus, the reasonable range for the population mean is (61%, 75%).

5 0

3 years ago

Mindy and Troy combined ate 9 99 pieces of the wedding cake. Mindy ate 3 33 pieces of cake and Troy had 1 4 4 1 start fraction

saul85 [17]

Answer:

(a)There are 24 cakes in total

(b)There are 15 pieces of cakes left

Step-by-step explanation:

Let the total cakes=x

Let number of cakes eaten by Mindy=m

Let number of cakes eaten by Troy=t

Now:

m=3

Since m+t=9

3+t=9

t=9-3=6

The Number of Pieces of Cake Left in Total=x-(t+m)

Since Troy had $\frac{1}{4}$ of the total cake

$\frac{1}{4} of x=6$

$\frac{1}{4} X x=6$

x=6X4=24

(a)There are 24 cakes in total

(b)The Number of Pieces of Cake Left in Total=x-(t+m)=24-9=15 cakes

5 0

3 years ago

Rachel recorded the number of calls she made at work during the week:

Dmitry [639]

The chi-squared test statistic will be 3.11. The test statistic is contrasted with a predicted value based on the Chi-square distribution.

<h3>What is the chi-squared test statistic?</h3>

Finding the squared difference between the actual and anticipated data values, then dividing that difference by the expected data values, constitutes the test statistic.

The formula for the chi-squared test statistic is;

$\sum \frac{(O_i-E_i)^2}{E_i } \\\\$

Where,

$\rm O_i$ is the observed value

$\rm E_i$ is the expected value

The chi-square test statics is;

$\rm( \frac{18-18}{18} )^2 +( \frac{14-18}{18} )^2 + (\frac{24-18}{18} )^2+( \frac{16-18}{18} )^2 \\\\ 0+ \frac{16}{18}+ \frac{36}{18} +\frac{4}{18}\\\\ \frac{56}{18} \\\\ 3.11$

Hence, the chi-squared test statistic will be 3.11.

To learn more about the chi-squared test statistic refer;

brainly.com/question/14082240

#SPJ1

5 0

2 years ago