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Karolina [17]
3 years ago
7

20 points NEED HELP

Mathematics
2 answers:
Finger [1]3 years ago
8 0
It would be C, because there are 700,000 people and with A, B, and D there are more people than there are the original population.
Mamont248 [21]3 years ago
8 0

Answer:

the answer is C

Step-by-step explanation:

hope this helps

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Consider the equation Ax+By=−36. If the x-intercept is (−3,0) and the y-intercept is (0,9), what are the values of A and B?
Grace [21]

Answer:

A= 12

B = -4

Step-by-step explanation:

( -3,0) & (0,9) should satisfy the equation Ax + By = -36

when ( -3,0)

-3A+ 0 = -36

A = 12

when (0,9)

0 + 9B = -36

B = -4

5 0
3 years ago
the area of square Garden is 625 metre square find its length its perimeter and find the cost of fencing it with 5 round at Rs 2
Mazyrski [523]

Answer:

Length=25m

Parameter=100m

5 round cost RS 12500

Step-by-step explanation:

The area of a square

=x²

According to the question the equation is

x²=625

x=√625

x=25

The parameter is

25×4

100 meter

So

1 meter costs 25

100 " " 25×100

2500

1 round = 100 meter

So

5 round cost 2500×5

12500

8 0
3 years ago
The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i
harina [27]

Answer:

a

   y(t) = y_o e^{\beta t}

b

      x(t) =  x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }

c

      \lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }

Step-by-step explanation:

From the question we are told that

    \frac{dy}{y} =  -\beta dt

Now integrating both sides

     ln y  =  \beta t + c

Now taking the exponent of both sides

       y(t) =  e^{\beta t + c}

=>     y(t) =  e^{\beta t} e^c

Let  e^c =  C

So

      y(t) = C e^{\beta t}

Now  from the question we are told that

      y(0) =  y_o

Hence

        y(0) = y_o  = Ce^{\beta * 0}

=>     y_o = C

So

        y(t) = y_o e^{\beta t}

From the question we are told that

      \frac{dx}{dt}  = -\alpha xy

substituting for y

      \frac{dx}{dt}  = - \alpha x(y_o e^{-\beta t })

=>   \frac{dx}{x}  = -\alpha y_oe^{-\beta t} dt

Now integrating both sides

         lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c

Now taking the exponent of both sides

        x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}

=>     x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c

Let  e^c  =  A

=>  x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }

Now  from the question we are told that

      x(0) =  x_o

So  

      x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }

=>    x_o = K e^{\frac {\alpha y_o  }{\beta } }

divide both side  by    (K * x_o)

=>    K = x_o e^{\frac {\alpha y_o  }{\beta } }

So

    x(t) =x_o e^{\frac {-\alpha y_o  }{\beta } } *  e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }

=>   x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }

=>    x(t) =  x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }

Generally as  t tends to infinity ,  e^{- \beta t} tends to zero  

so

    \lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }

5 0
3 years ago
Suppose A and B represent two different school populations where A > B and A and B must be greater than 0. Which of the follo
Virty [35]
<span>A+B)^2 is the largest.  It is A^2+2AB+B^2, which is clearly greater than the last two options.  To compare (A+B)^2 and 2(A+B), we remove one A+B so that we're just comparing A+B and 2.  As A+B must be at least 3 (as both must be positive integers, and one must be greater than the other, leading to a minimum value of A=2, B=1), A+B is greater than 2, and as a result, (A+B)^2 is always the largest.</span>
6 0
3 years ago
4) Which number would divide the numerator and the denominator of the first
pav-90 [236]

Answer:

2/2

Step-by-step explanation:

I think so, because 14/2 = 7 and 18/2 = 9

6 0
2 years ago
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