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alexdok [17]
3 years ago
11

Write 893 cm/2 as a fraction of 0.23 m/2

Mathematics
1 answer:
Nastasia [14]3 years ago
8 0

1 CENTIMETER SQUARES = 0.0001 METER SQUARES

How To Calculate Centimeter Squares To Meter Squares

To convert centimeter squares to meter squares you simply multiply your centimeter squares by 0.0001. The formula would look like this:

Ym2 = Xcm2 * 0.0001

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At a Psychology final exam, the scores are normally distributed with a mean 73 points and a standard deviation of 10.6 points. T
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Answer:

55.563

Step-by-step explanation:

Given the following :

Mean(m) point = 73

Standard deviation( sd) = 10.6

Lower 5% will not get a passing grade (those below the 5% percentile)

For a normal distribution:

The z-score is given by:

z = (X - mean) / standard deviation

5% of the class = 5/100 = 0.05

From the z - table : 0.05 falls into - 1.645 which is equal to the z - score

Substituting this value into the z-score formula to obtain the score(x) which seperates the lower 5%(0.05) from the rest of the class

z = (x - m) / sd

-1.645 = (x - 73) / 10.6

-1 645 * 10.6 = x - 73

-17.437 = x - 73

-17.437 + 73 = x

55.563 = x

Therefore, the score which seperetes the lower 5% from the rest of the class is 55.563

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3 years ago
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Step-by-step explanation:

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12 • 3 ÷ 9 - 2(4² - 10) + 8
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Step-by-step explanation:

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A student drew a circle and two secant segment. He concluded that if PQ ~= PS, Then QR ~= ST. Do you agree with the student’s co
9966 [12]

Answer:

  Yes

Step-by-step explanation:

You can get there a couple of ways. One makes use of the secant rules that tell you ...

  PQ × PR = PS × PT

Substituting for PR and PT, you have ...

  PQ × (PQ + QR) = PS × (PS + ST)

  PQ² + PQ×QR = PS² + PS×ST

Substituting PQ for PS everywhere, we have ...

  PQ² + PQ×QR = PQ² + PQ×ST

Dividing by PQ gives ...

  PQ + QR = PQ + ST

and subtracting PQ leads us to the conclusion ...

  QR = ST

_____

Another way to look at it is to draw the chord QS. Then ΔQPS is an isosceles triangle, and the perpendicular bisector of QS bisects ∠P and also goes through the circle center. Then the figure is symmetrical about that diameter secant, making QR ≅ ST.

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3 years ago
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