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3 years ago

4 - (7 + 2) ÷ 3pemdas please

Mathematics

2 answers:

Iteru [2.4K]3 years ago

7 0

The answer to the problem using pemdas is 1.

Viktor [21]3 years ago

3 0

Do the problem in the parentheses first
7+2=9
bring down the rest of the problem
4-9 ÷3
Divide 9 by 3= 3
bring down the 4 and subtraction sign
4-3=1
1 is your final answer

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3 years ago

Claire jogs 6 miles per hour and Megan jogs 5 miles per hour. they start together at their campsite and jog to an outpost 18 mil

horrorfan [7]

Answer:

16.364 miles

Step-by-step explanation:

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Claire time =( 18+x)/6

Megan Tim =( 18-x)/5

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3 years ago

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2 years ago

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Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

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$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
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$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o$

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4 - (7 + 2) ÷ 3pemdas please​

4 - (7 + 2) ÷ 3pemdas please