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emmasim [6.3K]
3 years ago
5

PLZ HELP IM BEING TIMED!!!

Mathematics
1 answer:
Deffense [45]3 years ago
8 0

Answer:

7√(x) = 14

Step-by-step explanation:

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Solve for x in simplest form (again) You don't need to write out the work for me, you can jus write down the answer you got.
FromTheMoon [43]

Answer:

x = 40/21

Step-by-step explanation:

This should be the right answer...

5 0
3 years ago
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One number is five more than a second number. The product of the numbers is 3,300. Find the two numbers
krek1111 [17]
A = b+5
ab = 3300
(b+5)b = 3300
b² +5b -3300 = 0  (quadratic formula)
b=55
a=60      (by first relation)
7 0
3 years ago
A tree grows three-fourth feet per year. How long will it take the tree to grow from
xenn [34]

Answer:

9 years

Step-by-step explanation:

37-21.25 =15.75ft

1.75ft per year

15.75  / 1.75  = 9 years

4 0
2 years ago
Find the following: F(x, y, z) = e^(xy) sin z j + y tan^−1(x/z)k Exercise Find the curl and the divergence of the vector field.
natulia [17]

\vec F(x,y,z)=e^{xy}\sin z\,\vec\jmath+y\tan^{-1}\dfrac xz\,\vec k

Divergence is easier to compute:

\mathrm{div}\vec F=\dfrac{\partial(e^{xy}\sin z)}{\partial y}+\dfrac{\partial\left(y\tan^{-1}\frac xz\right)}{\partial z}

\mathrm{div}\vec F=xe^{xy}\sin z-\dfrac{xy}{x^2+z^2}

Curl is a bit more tedious. Denote by D_t the differential operator, namely the derivative with respect to the variable t. Then

\mathrm{curl}\vec F=\begin{vmatrix}\vec\imath&\vec\jmath&\vec k\\D_x&D_y&D_z\\0&e^{xy}\sin z&y\tan^{-1}\frac xz\end{vmatrix}

\mathrm{curl}\vec F=\left(D_y\left[y\tan^{-1}\dfrac xz\right]-D_z\left[e^{xy}\sin z\right]\right)\,\vec\imath-D_x\left[y\tan^{-1}\dfrac xz\right]\,\vec\jmath+D_x\left[e^{xy}\sin z}\right]\,\vec k

\mathrm{curl}\vec F=\left(\tan^{-1}\dfrac xz-e^{xy}\cos z\right)\,\vec\imath-\dfrac{yz}{x^2+z^2}\,\vec\jmath+ye^{xy}\sin z\,\vec k

5 0
3 years ago
Which if of the following is not true.
guapka [62]

Answer:

It will be the last one

Step-by-step explanation:

This is because the slope for AB is 1/3 while BC is 2/3

Hope this Helped

6 0
3 years ago
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