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Colt1911 [192]
3 years ago
14

This is me. What is 50+ 50?

Mathematics
2 answers:
arsen [322]3 years ago
7 0

Answer:

100

tvtvtvtcxtexxxtuncd,d,w

sleet_krkn [62]3 years ago
3 0

Answer:

100

Step-by-step explanation:

because 50 + 50 = 100

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Answer Choices for picture below:
Nat2105 [25]

Answer:

Your answer: 5.(4,-4)

Step-by-step explanation:

Please mark brainliest and have a nice night/day!!

6 0
3 years ago
6/8w= -9/3<br><br> solve for w<br><br> pls hurry I need help I will give brainliest
Vesnalui [34]

Answer: w=−4

Step-by-step explanation:

hoped this helped

3 0
3 years ago
Which comparison is correct?<br> A. 7 -7<br> C. -9 &gt; 4<br> D. -6 &gt; -5
pashok25 [27]

Answer:

A is correct hope this helps

7 0
3 years ago
Read 2 more answers
Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of
Alexxx [7]

Answer:

a) 0.018

b) 0            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)

= 1 - P(z \leq 2.1)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%

0.018 is the probability that if an individual man is randomly​ selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected​ men, these men have a mean hip breadth greater than 16.5 in)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(x > 16.5)  

P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)  

= 1 - P(z \leq 23.29)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 1 = 0

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0
3 years ago
You have a handful of dimes and quarters that totals 26 coins and is worth $5.15. How many of each do you have?
borishaifa [10]

Answer:

9 dimes and 17 quarters

Step-by-step explanation:

9+17=26 coins

9 dimes = 90 cents

17 = 425 cents

90+425= 515 cents or $5.15

Hope this helps! :)

5 0
3 years ago
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