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trapecia [35]
3 years ago
12

Mid chapter checkpoint 5th grade chapter 2 writing questions

Mathematics
1 answer:
Alecsey [184]3 years ago
7 0

Estimation simply means an approximated value.

  • <em>Estimation gives the range of the first digit of the quotient</em>
  • <em>Multiplication is the inverse of division.</em>
  • <em />663 \div 3 = 112<em>.</em>
  • <em />487 \div 8 = 60\ R\ 7<em>.</em>
  • <em />1641 \div 4 = 410\ R\ 1<em>.</em>
  • <em />2765 \div 9 = 307\ R\ 2<em />

<em />

<u />

<u />

<u>Estimation in whole-number quotient</u>

A whole number quotient is represented as:

\frac ab = c

Where:

<em />a,b, c \to<em> whole numbers</em>

When the numbers are estimated, one would get the idea of the range of values the first digit can assume.

<u>Take for instance:</u>

\frac{117}{3}

117 can be estimated as 120. So, we have:

\frac{117}{3} \approx \frac{120}{3}

<em>120 divided by 3 is 40.</em>

The first digit of <em>120 divided by 3 </em>is 4.

So, estimating 117 as 120 makes us know that the first digit of <em>117 divided by 3 </em>would either be 4 or less.

<u />

<u>(b) Multiplication in division problem</u>

Multiplication and division are both inverse operations.

So, multiplication is used to check the dividend of the division problem.

Take for instance:

\frac{117}{3} = 39

<em>If the above division is correct, then 39 multiplied by 3 must be 117 i.e.</em>

39 \times 3 = 117

(c)\ 663 \div 3

Start by dividing the first 6 by 3

663 \div 3 \to 1

Divide the next 6 by 3

663 \div 3 \to 11

Divide the last 3 by 3

663 \div 3 = 112

(d)\ 487 \div 8

Divide 4 by 8

487 \div 8 \to 0

Since the result is 0 and 4 is not the last digit, we then try 48.

Divide 48 by 8

487 \div 8 \to 06

Divide 7 by 8.

487 \div 8 \to 060

7 is less than 8; this means that 8 cannot divide 7.

So, we write 7 as the remainder

487 \div 8 = 060\ R\ 7

Remove the leading 0

487 \div 8 = 60 R 7

(e)\ 1641 \div 4

Divide 1 by 4

1641 \div 4 \to 0

Divide 16 by 4

1641 \div 4 \to 04

Divide 4 by 4

1641 \div 4 \to 041

Divide 1 by 4

1641 \div 4 \to0410

1 is less than 4; this means that 8 cannot divide 1.

So, we write 1 as the remainder

1641 \div 4 \to 0410\ R\ 1

Remove the leading 0

1641 \div 4 = 410\ R\ 1

(f)\ 2765 \div 9

Divide 2 by 9

2765 \div 9 \to 0

Divide 27 by 9

2765 \div 9 \to 03

Divide 6 by 9

2765 \div 9 \to 030

6 is less than 9; this means that 9 cannot divide 6.

So, the next division will be 65 by 9

2765 \div 9 \to 0307

9 divides 63 in 7 places, with a remainder of 2.

So, we have:

2765 \div 9 = 0307 R 2

Remove the leading 0

2765 \div 9 = 307 R 2

Read more about division and multiplications at:

brainly.com/question/19928607

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