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3 years ago

In the coordinate plane, point W is located at (-11,35). If point W is reflected across the x-axis, what are he new coordinates

Mathematics

1 answer:

aev [14]3 years ago

7 0

Answer:

The new coordinates are (-11, -35)

Step-by-step explanation:

When reflecting across the x-axis, you are just the Y. value. It is the opposite due to the fact that if you're moving something across the horizontal x-axis, it's actually the vertical height changing. So, you just inverse the Y value to its' negative or positive reciprocal.

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Neglecting air resistance and the weight of the propellant, determine the work done in propelling a four-ton satellite to the fo

balandron [24]

Answer:

Step-by-step explanation:

Work = force × distance

force = mass × acceleartion due to gravity

a four ton satellite will have a force of 4× 1000 ×10 = 40KN (1000Kg = 1 ton)

1 mile = 1609.34 metre

therefore (a) 100 miles above the earth

work = 40000 × 100×1609.34

= 6437360000J

=6.4GJ

(b) 300 miles above the earth

work = 40000×300×1609.34

= 1.93×10¹⁰ J

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3 years ago

Find the measure of the missing angles

serg [7]

Answer:

y = 57° and x = 33°

Step-by-step explanation:

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2 years ago

Find m∠A. Put the answer below. m∠A =

vladimir1956 [14]

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3 years ago

Solve for w. 0.05w = 15

steposvetlana [31]

In order to find the value first multiply both sides by 100 to simplify the equation:
0.05w*100=15*100
5w=1500
Next, divide both sides of the equation by 5:
5w/5=1500/5
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The final solution is w=300!

Hope i could help.
have a great day

4 0

3 years ago

Read 2 more answers

Optimization Calculus Problem

frosja888 [35]

$\bf \begin{cases}
V_c=\textit{cylinder's volume}\\
V_h=\textit{hemisphere's volume}\\
A_c=\textit{area of the cylinder}\\
A_h=\textit{area of the hemisphere}
\end{cases}
\\\\\\
V_c+V_h=6000\implies (\pi r^2h)+\left( \frac{2\pi r^3}{3} \right)
\\\\\\
6000=\cfrac{3\pi r^2h+2\pi r^3}{3}\implies 18000-2\pi r^3=3\pi r^2h
\\\\\\
\boxed{\cfrac{6000}{\pi r^2}-\cfrac{2r}{3}=h}
\\\\
-------------------------------\\\\$

$\bf A_c=2\pi rh+2\pi r^2\implies A_c=2\pi r\left(\cfrac{6000}{\pi r^2}-\cfrac{2r}{3} \right)+2\pi r^2
\\\\\\
A_c=\cfrac{12000}{r}-\cfrac{4\pi r^2}{3}\impliedby \textit{say it has a cost of 1, so stays the same}\\\\
-------------------------------\\\\
A_h=2\pi r^2\impliedby \textit{has a cost of 8 times the cylinder's}
\\\\\\
A_h=16\pi r^2\\\\
-------------------------------\\\\$

$\bf \textit{total cost is }A_c+A_h
\\\\\\
\cfrac{12000}{r}-\cfrac{4\pi r^2}{3}+16\pi r^2\implies \cfrac{12000}{r}-\cfrac{4\pi r^2}{3}+\cfrac{48\pi r^2}{3}
\\\\\\
\boxed{C(r)=\cfrac{12000}{r}+\cfrac{44\pi r^2}{3}}$

7 0

3 years ago