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3 years ago

HELPP PLSS ILL MARK BRIANLIEST

Mathematics

1 answer:

Murrr4er [49]3 years ago

7 0

Answer:

128cm

Step-by-step explanation:

Your Welcome :)

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The interior angles of a triangle are 60,45and 75.the shortest side is 10cm less than the longest side, determine the perimeter

masha68 [24]

Answer:

Step-by-step explanation:

We know that the permiter is defined as

$P=L+S+M$

Where $L$ is the longest side, $S$ is the smallest and $M$ is the middle side.

If $L=x$ then, $S=x-20$ , where we need to find an expression for $M$ using the law of cosines.

$M^{2} =L^{2}+S^{2}-2 \times L \times S \times cos(60\°)\\M=\sqrt{x^{2}+(x-20)^{2}-x(x-20)}\\M=\sqrt{x^{2} +x^{2}-40x+400-x^{2}+20x}=\sqrt{x^{2}-20x+400}$

Replacing all expression, the perimeter is

$P=x+x-20+\sqrt{x^{2}-20x+400}\\P=2x-20+\sqrt{x^{2}-20x+400}$

Using a calculator, the perimeter is 20 units centimeters.

7 0

3 years ago

X+y=6 and 2x-y=3. The system of equations ...has no solution, has one solution, or is coincident

Keith_Richards [23]

x+y=6

2x-y=3

3+3=6

2×3-3=3

3+3=6

6-3=3

5 0

3 years ago

125% of x is 60. What is x

Lunna [17]

Answer:

Step-by-step explanation:

1.put your percent over a 100 so

125%/100 then put 60 over x

2.then cross multiply 100x60=6000

3.then divide 6000 by 125 which is percent

4.your answer is-48

8 0

3 years ago

Read 2 more answers

There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit

Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a $\frac{3}{11}$ chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is $\frac{8}{11}$ , and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

$\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}$

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is $\frac{2}{11}$ , and the probability of picking the second red ball is $\frac{1}{10}$ and the probability of picking the green ball is $\frac{1}{9}$ . We want to multiply thm again, as per the multiplication rule like the last problem.