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QveST [7]
3 years ago
13

Help I need to submit soon

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
8 0

Answer:

4

Step-by-step explanation:

I don't know if u want the explanation

Y_Kistochka [10]3 years ago
5 0
I got 4 as the answer
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A cell phone plan costs $200 to start. Then there is a $50 charge each month
Serga [27]

Answer:Depending on how high u do it either by 0,25,50 or 0,50,100

Step-by-step explanation:

7 0
2 years ago
How can I find an outlier in a box and whisker plot?
Temka [501]

Answer:

Generally it's one that is just out of the way, the extreme outcast.

4 0
3 years ago
A recipe for banana bread requires 3 cups of bananas for every 1 1/2 cups of sugar used.At this rate,how many cups of sugar shou
arsen [322]

Answer: 1 cup of sugar

Step-by-step explanation:

A recipe for banana bread requires 3 cups of bananas for every 1 1/2 cups of sugar used.

Converting 1 1/2 cups of sugar to improper fraction becomes 3/2 cups of sugar.

If 3 cups of bananas is required for 3/2 cups of sugar,

x cups of bananas will require 1 cup of sugar

3x / 2 = 3

3x = 6

x = 6/3 = 2

Therefore,

2 cups of bananas will require 1 cup of sugar.

We are looking for the number of cups of sugar that would require 2 cups of bananas.

We already got the answer.

1 cup of sugar would be used if 2 cups of bananas are used.

6 0
3 years ago
The sum of 5 consecutive integers is 110, what is the fourth number in this sequence?
Xelga [282]

The answer is:  " 23 " .

    →  The fourth number in the sequence is:  " 23 " .

_____________________________________

Explanation:

To solve:

 " x + (x + 1) + (x + 2) + (x + 3)  + (x + 4) = 110 " ;

in which:

 "x" = The first number in these sequence;

 "(x + 1 )" = the second number in the sequence;

 "(x + 2)" = the third number in the sequence;

 "(x + 3)" = the fourth number in the sequence;

 "(x + 4)" = the fifth number in the sequence;

_____________________________________

Solve for the "fourth number in the sequence" ; or:  "(x + 3)" ;

_____________________________________

Given:  " x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 110 " ;

                     ↔   " x + x + 1 + x + 2 + x + 3 + x + 4 = 110 " ;

→  Solve for "x" ;  

→  then,  solve for "(x + 3)" ;  

     →  which is the fourth number in this sequence;

_____________________________________

→  " x + x + 1 + x + 2 + x + 3 + x + 4= 110 " ;

      "5x + 1 + 2 + 3 + 4= 110 " ;

      " 5x + 10 =  110 " ;

Solve for "x" :

     Subtract "10" from EACH SIDE of the equation; as follows:

      " 5x + 10 - 10 =  110 - 10 " ;

 to get :

      "  5x = 100 " ;

Now, divide EACH SIDE of the equation by "5" ;

to isolate "x" on one side of the equation; & to solve for "x" ;  as follows:

         5x / 5  = 100 / 5 ;

to get:

         "  x  = 20 "  .

_____________________________________

Now, to find the fourth number in the sequence:

 →  " (x + 3) " ;

→  Substitute "20" for "x" ;

    " x + 3 = 20 + 3 = 23" ;

_____________________________________

The answer is:  " 23 " .

The fourth number in the sequence is:  " 23 " .

_____________________________________

Let us check our work:

If there are five "5" numbers in the sequence, and "23" is the "fourth number" , then:  "24" is the "fifth number" .

As such:  "22" is the "third number" ;  "21" is the "second number" ; and "20" is the "first number" .  Is this consistent with:  "x = 20" as the "first number" ?  Yes!

Thus,  "20 + 21 + 22 + 23 + 25 = ?  110 ?  ? ;

→  20 + 21 = 41 ;

→  41 + 22 = 63 ;

→  63 + 23 = 86 ;

→  86 + 24 = 110 .    Yes!

_____________________________________

Hope this answer is helpful!

Best wishes in your academic pursuits—

 and within the "Brainly" community!

_____________________________________

5 0
3 years ago
Members of a college chemistry department agree to contribute equal amounts of money to make up a scholarship fund of $280. Then
Zarrin [17]

Answer:

7 members

Step-by-step explanation:

Lets say that the department has n members. If each member contributes with an equal amount x and make a total of $280, we know that:

n*x = 280

Where each one colaborated with:

n*x/n = 280/n

Or what is the same that: (as the n on the left eliminate themselves)

x = 280/n (*)

Now the department hires 3 more members, so we now have n+3 members. And we know that the pass from contributing x to contribute $30 less, it is, x-30 (I omit the $ symbol for simplicity). So, know we have:

x-30 = 280/(n+3)

We can replace x here by the formulation of x we did in the (*) equation:

( 280/n) - 30 = 280/(n+3)

using common denominator:

( 280/n) - 30 n/n = 280/(n+3)

( 280 - 30 n)/n = 280/(n+3)

Cross multiplying the denominators:

( 280 - 30 n)*(n+3) = 280*(n)

280n - 30n^2 + 840 - 90n = 280n

Subtracting 280 n in both sides:

30n^2 + 840 - 90n = 0

Dividing both sides by 30:

-n^2 - 3n + 28 = 0

Factorizing this term (you can notice the factor immediately or solving with baskara resolution, I omit the baskara for simplicity):

-(n + 7)(n - 4) =0

So, n is equal to 4 and -7. As we are dealing with people we can not have -7 people, so we keep only n=4.

So, previous the new hiring there were 4 members, now there are 7.

The used to collaborate with 280/4 = $70, now the collaborate with 280/7=$40, and we see the collaboration decreased in $30.

7 0
3 years ago
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