My age is the difference between twice my age in 4 years and twice my age 4 years ago how old am I?
1 answer:
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Sin = - 4/8
Quadrant IV = only cosine is positive
a = height (4)
b = base ( 8^2-4^2=b^2
b = 6.93 @
c = hypothenuse(8)
cos =
/8
tan = - 4/
sec = 1/cos
1/cos = 1/ (
/8)
sec = 8/
csc = 1/sin
1/sin = 1/(-4/8)
csc = - 2
cot = 1/tan
1/tan = 1/(-4/
)
cot = -
/4
Quadrant IV = only cosine is positive
a = height (4)
b = base ( 8^2-4^2=b^2
b = 6.93 @
c = hypothenuse(8)
cos =
/8
tan = - 4/
sec = 1/cos
1/cos = 1/ (
/8)
sec = 8/
csc = 1/sin
1/sin = 1/(-4/8)
csc = - 2
cot = 1/tan
1/tan = 1/(-4/
)
cot = -
/4
Answer:
Thus, option (c) is correct.
β = 61.5
Step-by-step explanation:
Given , , we have to solve for x, and then find the value of β ( β > α )
Consider ,
First solve for x ,
Thus,
Also, , we get,
Thus,
since, LHS = RHS thus, angle must be equal,
Thus, ,
Other angle can be found using angle sum property, as sum of angle of a triangle is 180°
Let third angle be y, then ,
90 + 61.5 + y = 180°
y = 180° - 151.5°
y = 28.5°
Since ( β > α ) ⇒ β= 61.5 and α = 28.5
Thus, option (c) is correct.
⇒ β = 61.5