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2 years ago

My age is the difference between twice my age in 4 years and twice my age 4 years ago how old am I?

Mathematics

1 answer:

Llana [10]2 years ago

6 0

Answer: 16

Step-by-step explanation:

let a = your present age

a = 2(a+4) - 2(a-4)

a = 2a + 8 - 2a + 8

a = 2a - 2a + 8 + 8

a = 16 yrs is your age

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BartSMP [9]

Answer:

-3x+30

Step-by-step explanation:

$4\left(x+7\right)-7x+2$

Expand $4(x+7)= 4x+28$

$4x+28-7x+2$

Simplify $4x+28-7x+2$

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2 years ago

Write in exponential notation: 301=

dalvyx [7]

Answer:

$3.01 * 10^2$

Step-by-step explanation:

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2 years ago

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

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1 year ago

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kirza4 [7]

Answer:

1111111 is the answer

Step-by-step explanation:

8 0

3 years ago

In a certain clothing store, 6 shirts and 3 ties cost $79.50, and 3 shirts and 2 ties cost $41. Determine the cost of each tie.

Genrish500 [490]

6x + 3y = 79.5
3x + 2y = 41 y = -3/2x + 41/2 y = -1.5x + 20.5

6x + 3(-1.5x + 20.5) = 79.5
6x - 4.5x + 61.5 = 79.5
1.5x + 61.5 = 79.5
1.5x = 18
x = 12

Each shirt costs $12.
Now insert that number into the x to find the cost of each tie.

3(12) + 2y = 41
36 + 2y = 41
2y = 5
y = 2.5

Each tie costs $2.50.

4 0

2 years ago