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2 years ago

What is the instantaneous rate of change of f(x)=xe^x-(x 2)e^(x-1) at x=0 ?

1 answer:

8 0

You have to derive for a multiplication in both terms:
=e^x+xe^x-(e^x-1 + (x-2)e^x-1) now apply distributive property in the last term:
=e^x+xe^x+e^x-1-xe^x-1 now replace each x by 0 (x=0)
=1 + 0 + e^-1 + 0 = 1+ e^-1 = 1.3679

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6 to the fourth power divided by 3 to the second power over 9

zhannawk [14.2K]

Answer:

Step-by-step explanation:

(6^4/3^2)/9=16

3 0

2 years ago

It always seems to rain on the day after July 4th.

Rina8888 [55]

Answer:

The inductive reasoning is based on A: a limited number of observations

Step-by-step explanation:

Let's say you lived until 90 years old, and took a observation on July 4th each year. Even if you lived until 90 years old, you would only have 90 observations. And inductive reasoning allows for statements to be false, so any of the 90 observations that you took can be proven false. So really, you would have only 90 observations, with any of them that could be false. A limited number of observations would be the only thing that you could base this reasoning off of.

7 0

2 years ago

A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are

Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that $p = 0.75$ , and four games means that $n = 4$

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164$

0.3164 = 31.64% probability the team wins all its conference games

4 0

2 years ago

Solve this equation for k.<br><br> 3 − 3k + 7k = 5b<br><br> Enter the correct answer in the box.

Sloan [31]

Answer:

k=5b/4−3/4

Step-by-step explanation:

3-3k+7k=5b

Isolate the variable by dividing each side by factors that don't contain the variable.

k=5b/4−3/4

-hope it helps

8 0

2 years ago

Help me solve this pleaseee

Drupady [299]

Since they are equal to 90 degrees. (complimentary angles)

6x-11+7x+10= 90

Combine like terms.

13x-1= 90

Add one to both sides.

13x= 91

x= 7

Plug that into the b.

7(7)+10

49+10

59

I hope this helps!
~kaikers

3 0

3 years ago