What is the instantaneous rate of change of f(x)=xe^x-(x 2)e^(x-1) at x=0 ?

1 answer:

8 0

You have to derive for a multiplication in both terms:
=e^x+xe^x-(e^x-1 + (x-2)e^x-1) now apply distributive property in the last term:
=e^x+xe^x+e^x-1-xe^x-1 now replace each x by 0 (x=0)
=1 + 0 + e^-1 + 0 = 1+ e^-1 = 1.3679

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For what percentage of time has life existed on earth (round to the nearest whole number).

abruzzese [7]

This is the concept of arithmetic. To calculate the percentage of time life has existed we proceed as follows;
According to history:
The age of earth is 4.6 billion years
the age of life is as it appeared from unicellular is 3.8 billion years.
thus the percentage of the above will be:
3.8/4.6 x 100
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6 0

3 years ago

1/4+1/2=____<br> Simplest form

LUCKY_DIMON [66]

Hello!

To find our answer, we first convert 1/2 into fourths. We multiply it by 2/2, giving us 2/4.

2/4+1/4=3/4

Therefore, our answer is $\boxed {\frac{3}{4}}$ .