Explanation
Problem #2
We must find the solution to the following system of inequalities:

(1) We solve for y the first inequality:

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

The solution to this inequality is the set of all the points (x, y) over the line:

This line has:
• slope m = 3/2,
,
• y-intercept b = -2.
(2) We solve for y the second inequality:

The solution to this inequality is the set of all the points (x, y) below the line:

This line has:
• slope m = -1/3,
,
• y-intercept b = 2.
(3) Plotting the lines of points (1) and (2), and painting the region:
• over the line from point (1),
,
• and below the line from point (2),
we get the following graph:
Answer
The points that satisfy both inequalities are given by the intersection of the blue and red regions:
Answer:
1/6
Step-by-step explanation:
Since there is only 1 letter R in 6 options it is 1/6 (im not entirely sure)
Answer:
14/13
Step-by-step explanation:
the reciprocal is the fraction upside down.
Answer:
20
Step-by-step explanation:
You have to look for -3 on the x axis, and then proceed vertically (in this case upwards) until you meet the graph.
We land about 1/2 square above the 12 mark on the y axis. Since one square is 1/2 unit, a half square would be 1/4 unit.
So, we can estimate 