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Stolb23 [73]
2 years ago
8

-8z+(4.5)+3.5z+7y-1.5

Mathematics
1 answer:
bogdanovich [222]2 years ago
6 0

Answer:

  • \boxed{\sf{7y+3-4.5z}}

Step-by-step explanation:

In order to combine like terms, you have to isolate x and y from one side of the equation.

\sf{-8z+\left(4.5\right)+3.5z+7y-1.5}

<u>First, thing you do is remove parentheses.</u>

\Longrightarrow: \sf{-8z+4.5+3.5z+7y-1.5}

<u>Solve.</u>

<u>Then, you combine like terms.</u>

\Longrightarrow:\sf{-8z+3.5z+7y+4.5-1.5}

<u>Add/subtract the numbers from left to right.</u>

-8z+3.5z=-4.5z

<u>Rewrite the problem down.</u>

\Longrightarrow: \sf{-4.5z+7y+4.5-1.5}

<u>Solve.</u>

4.5-1.5=3

\Longrightarrow: \boxed{\sf{7y+3-4.5z}}

  • <u>Therefore, the correct answer is 7y+3-4.5z.</u>

I hope this helps, let me know if you have any questions.

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Step-by-step explanation:

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Q(3x)=12x+2 then what is Q(x-2)
Mandarinka [93]

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Step-by-step explanation:

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2 years ago
The diameter of a circle is 23 inches and the circle has two chords of length 14 inches what is the distance from each chord to
Svetradugi [14.3K]

Answer:

9.12 + 9.12 = 18.24 inches

Step-by-step explanation:

Diameter = 23 inches (given)

Radius = 11.5 inches

2 Chords of length = 14 inches ( You didn't specify if the 14 inches is for both chords or for a single cord. I'll assume it's for two cords 14 and 14inches apart.

To clearly solve this, we'll make some mild assumptions.

Let the perpendicular distance of the chords from the center of the circle to represented as " x and y"

Therefore:

x^2 + 7^2 = 11.5 ^ 2

x^2 + 49 = 132.25

x^2 = 132.25 - 49

x^2 = 83.25

x = √ 83.25

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Since the cords have thesame length (Assumed from the way the question was structured, the distance would still be thesame)

y^2 + 7^2 = 11.5 ^ 2

y^2 + 49 = 132.25

y^2 = 132.25 - 49

y^2 = 83.25

y = √ 83.25

y = 9.12 inches

Therefore, the distance will be :

9.12 + 9.12 = 18.24 inches

Have fun!

6 0
4 years ago
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