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3 years ago

12080 gallons per month into liters per hour

Mathematics

2 answers:

Marat540 [252]3 years ago

7 0

<h3>12080 gallons/month = 63.511 liters/hour</h3>

<h3>Further explanation</h3>

Some units of length and its conversion that need to be recalled are:

$1 ~ foot = 30.48 ~ cm$

$1 ~ inch = 2.54 ~ cm$

$1 ~ foot = 12 ~ inches$

$1 ~ mile = 1609.34 ~ metres$

$1 ~ yard = 0,9144 ~ metres$

$1 ~\mu m = 1 \times 10^{-6} ~ m$

$1 ~ US ~ liquid ~ gallon = 3.78541 ~ litres$

Some units of time and its conversion that need to be recalled are:

$1 ~ month = 30 ~ days$

$1 ~ day = 24 ~ hours$

$1 ~ hour = 60 ~ minutes$

$1 ~ minute = 60 ~ seconds$

Let us now tackle the problem !

<u>Given:</u>

$12080 ~ \text{gallons/month} = \frac{12080 ~ \text{gallons}}{1 ~ \text{month}}$

$12080 ~ \text{gallons/month} = \frac{12080 \times 3.78541 ~ \text{liters}}{1 \times 30 \times 24 ~ \text{hours}}$

$12080 ~ \text{gallons/month} = \frac{45727.7528~ \text{liters}}{720 ~ \text{hours}}$

$12080 ~ \text{gallons/month} \approx 63.511 ~ \text{liters/hour}$

<h3>Learn more</h3>

Velocity of Runner : brainly.com/question/3813437
Kinetic Energy : brainly.com/question/692781
Acceleration : brainly.com/question/2283922
The Speed of Car : brainly.com/question/568302
A human Hair Diameter : brainly.com/question/1739172

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Unit of Length and Time

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Length , Microscope , Gallons , Month , Liters , Hour , Time

ryzh [129]3 years ago

4 0

Keeping in mind that, there are 3.78 liters in 1 US gallon and say 30days per month and 24 hours in a day.. then

$\bf \cfrac{12080~\underline{g}}{\underline{month}}\cdot\cfrac{3.78~liter}{\underline{g}} \cdot \cfrac{\underline{month}}{30~\underline{day}}\cdot \cfrac{\underline{day}}{24~hr}\implies \cfrac{12080\cdot 3.78~liter}{30\cdot 24~hr}
\\\\\\
\cfrac{45662.4~liter}{720~hr}\implies 63.42\frac{liter}{hr}$

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Step-by-step explanation:

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Find the slope AC

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Note The complete answers in the attached file

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Step-by-step explanation:

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