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blsea [12.9K]
3 years ago
6

How do you use change of base formula​

Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0

Answer:

According to the change-of-base formula, we can rewrite the log base 2 as a logarithm of any other base. Since our calculators can evaluate the natural log, we might choose to use the natural logarithm, which is the log base e.

Step-by-step explanation:

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OABCD is a pyramid with a rectangular base of sides 15cm by 9cm.Given that the slant height OQ is 16cm find its
crimeas [40]

Hello! Your answer is below... Remember : h = height and v = volume

Answer:

H = 15.35 cm

V = 690.75 m^

Step-by-step explanation:

(H= height, V = volume, ^= square, √ = square root )

1. divide 9/2

=4.5 cm

2. use the pythagorean theorem

H=√16^-4.5^

H=15.35

if your looking for volume

1. use the formula for volume of the pyramid which is:

1/3 x base area x height

or

base area x height /3

2. then you substitute

1/3 x (9)(15) x 15.35

or

(9)(15) x 15.35 /3

V= 690.75 m^

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

:)

3 0
3 years ago
Read 2 more answers
For what value of p would the statement 5p = 30 be true?<br>​
shtirl [24]

Answer:

6

Step-by-step explanation:

divide both sides of the equals by 5 to get p on its own

5p divided by 5 = p

30 divided by 5 = 6

6 0
3 years ago
Find the mean, median and mode of the given data? 8, 10,11, 8, 14,18, 8, 10, 11, 8, 15​
Inessa05 [86]

Answer:

it might be 18 ❤

Step-by-step explanation:

I'm pretty sure it is 18 let me know

5 0
2 years ago
100 is divisible by which of the following numbers 2,3,4,5,6,9 or 10?
pochemuha
The correct answer is B: 2,4,5, 10

We know that 100 is not divisible by 3 because 100/3 is 33.33 repeating, which is an irrational number.

We also know that 100 is not divisible by 6 because 100/6 is 16.66 repeating which is also an irrational number.

100/2=50 (rational)
100/4=25 (rational)
100/5=20 (rational)
100/10=20 (rational)

Hope this helps!
6 0
3 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
2 years ago
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