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2 years ago

What is the area of 3.14 x 20

Mathematics

2 answers:

tiny-mole [99]2 years ago

7 0

20 x 3.14 = 62.8 i hope this helps!

7nadin3 [17]2 years ago

6 0

Answer:

62.8

Step-by-step explanation:

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Select all of the following graphs which represent y as a function of x

Elden [556K]

A, B, D, and E are correct.

What makes these a function and the others not is that for each x value, there is only one y value. For C, for example, there are multiple y values for the x value of -2. The same goes for F.

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2 years ago

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A construction company wants to hire carpenters for $220 a day and plumbers for $260 a day. The company wants to hire at least 1

joja [24]

Answer:

Step-by-step explanation:

Yes the company can hire 6 carpenters and 12 pumbers

So first lets find out how much it costs to have 6 carpenter for $220 a day.

$220 × 6 = $1320 this is how much it cost to pay 6 carpenters for one day.

Now lets find how much it cost to 12 plumbers at $260 a day.

$260 × 12 = $3120 this is how much it costs to pay 12 plumbers a day.

The total amount you have to pay to the workers is:

$3120 + $1320 = $4440

Your budget was $4500 so the total costs for the workers is $4440 which means you can hire those workers and you would still have $60.

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2 years ago

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

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1 year ago

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Nadya [2.5K]

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Step-by-step explanation:

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2 years ago