All categories

2 years ago

(2 to the power -1 ÷ 5 to the power- 1)2 × -5/8 to the power -1

Mathematics

2 answers:

Luba_88 [7]2 years ago

8 0

Answer:

-8

Step-by-step explanation

2 to the power of -1 = 0.5

5 to the power of -1 = 0.2

0.5/0.2 = 2.5

So,

(2.5)2 x -5/8 to the power of -1

-5/8 = -0.625

-0.625 to the power of -1 = -1.6

So,

(2.5)2 x -0.625

5 x -0.625

= -8

san4es73 [151]2 years ago

3 0

Answer:

-8

Step-by-step explanation:

(2^-1 ÷ 5^-1) = 5/2

(5/2) x 2 = 10/2 or 5

-5/8 ^-1 = - 8/5

5 x - 8/5 = -40/5 or -8

Hope its helpful ☺️

You might be interested in

Find a statement that is equivalent to the absolute value equation |9x−9|=7.

Olegator [25]

Answer:9x-9=7 or 9x-9=-7

Step-by-step explanation:

An absolute value is the distance from zero, therefore the answer can not be negative. In this case, 9x-9=7 and 9x-9=-7 both work, because 7 and -7 are the same distance from zero.

8 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

A rectangular gasoline tank can hold 45.0 kg of gasoline when full. what is the depth of the tank if it is 0.450 m wide by 0.900

garri49 [273]

The answer is 0.154 m

Step 1. Calculate the volume of gasoline tank (V) using the known mass (m) and density of gasoline (D).
D = m/V
⇒ V = m/D
D = 719.7 kg/m³
m = 45.0 kg
V = 45.0 kg/719.7 kg/m³ = 0.0625 m³

Step 2. Calculate the depth of the tank (d) using the known volume (V) of gasoline and width (w) and length (l) of the tank:
V = d * w * l
0.0625 = d * 0.900 * 0.450
0.0625 = d * 0.405
d = 0.0625 / 0.405
d = 0.154 m

7 0

3 years ago

Which of the following is a linear function?

djyliett [7]

It should be the last option. With linear functions, you should be graphing a straight line.

3 0

2 years ago

1+1 pls fast right now

Marianna [84]

Answer:

Step-by-step explanation:

smarty pants obv

3 0

2 years ago

Read 2 more answers

(2 to the power -1 ÷ 5 to the power- 1)2 × -5/8 to the power -1​

(2 to the power -1 ÷ 5 to the power- 1)2 × -5/8 to the power -1