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mina [271]
3 years ago
10

A rectangular field is 120 yards long and 85 yards wide.

Mathematics
2 answers:
stepladder [879]3 years ago
8 0

Answer:

Ans is in attachment

hope it helps :)

plz mark as brainliest

kakasveta [241]3 years ago
3 0

Step-by-step explanation:

Given parameters:

Length = 120yards

Width  = 85yards

Unknown:

Length and width of another rectangular field with the same perimeter but a larger area = ?

Solution:

The key to solving this problem is to known that for any given length and width, the area of square is the greatest.

  Length = 120yards     New length  = 100yards

 Width  = 85yards         New width = 105yards

Now,

 Area of the new dimension  = 105 x 100  = 10500yd²

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Answer:

3/2

I hope this is correct

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3 years ago
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bob makes 24 oz of orange juice he pours equal amounts of juice into 5 cups the amount of juice in each cup will fall between wh
Yuri [45]

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3 years ago
I made a square frame for my favorite bird picture from four wooden pieces. Each piece is a rectangle with a perimeter of 24 inc
kupik [55]

Answer:

The perimeter of the picture frame is 38.4 in.

The area of the picture frame is 92.6 in.².

Step-by-step explanation:

The given information are;

Perimeter of side piece of picture frame = 24 inches

Length of side piece = L

Width of side piece = W

Perimeter of side piece = 2 × (L + W) = 24

∴ L + W = 24/2 = 12 inches

Dimension of picture frame = Square frame with side length s

Number of side piece in picture frame = 4

Given that the length L > the width W, we have

Side length of wooden frame = L

Also, where the side piece are placed side by side, we have;

Side length of wooden frame = 4 × W

Therefore;

4 × W = L

Which gives

L + W = 12 inches

4 × W + W = 12 inches

W×(4 + 1) = 5·W = 12 inches

W = 12/5 = 2.4 inches

L = 4 × W = 4 × 12/5

L = 48/5 = 9.6 inches  Side length of wooden frame, s

The perimeter of the picture frame = 4 × s = 4 × 9.6 = 38.4 in.

The area of the picture frame = s × s = 9.6 × 9.6 = 92.6 in.².

7 0
3 years ago
Howdy!
posledela

Answer:

A) Central angle has same measure as intercepted arc.

  • mCE = mCD + mDE = 20° + 90° = 110°

B) Opposite angles of cyclic quadrilateral are supplementary.

  • mRL = 2*m∠PQR - mPL = 2*74° - 72° = 76°
  • m∠QPL = (1/2)mQRL = (1/2)(90° + 76°) = 83°
  • m∠QRL = 180° - m∠QPL = 180° - 83° = 97°
  • mQP = 360° - (90° + 76° + 72°) = 122°

C)

  • m∠MLN = m∠MRN as same arc MN is intercepted
  • m∠LMN is right angle as opposite side is diameter.
  • ∠MNL is complementary with ∠MLN which is same as ∠MRN
  • m∠MNL = 90° - 47° = 43°

D) Tangent secant angle is half of the intercepted arc.

<em>It seems wrong. Should be mQP instead of mQR</em>

  • mQP = 2*m∠RQP = 2*74° = 148°
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