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Nitella [24]
2 years ago
11

Slope between (-2,11) 5,6)

Mathematics
2 answers:
madreJ [45]2 years ago
5 0

Answer:

-\frac{5}{7}

Step-by-step explanation:

Slope = \frac{rise}{run}

          = \frac{6-11}{5-(-2)}

          = \frac{6-11}{5+2}

          = \frac{-5}{7}

          = -\frac{5}{7}

Nat2105 [25]2 years ago
5 0

Answer:

To calculate the slope, you can first substract the points to get the vector that join both, you may do it like this:

(-2, 11) - (5,6) = (-2 - 5, 11 - 6) = (-7, 5)

To get the slope when you get the vector (x,y), you will have to divide y be x:

5/-7

So the slope is 5/-7, -\frac{5}{7}

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To get your answer, you would divide your distance by your speed. You should be going about 1.4 miles per hour.

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3 years ago
(-6,-4) and is parallel to the line x+6y=12
HACTEHA [7]

Answer: y = -\frac{1}{6}x-5

Step-by-step explanation:

x+6y=12

6y=-x+12

y=-\frac{x}{6} + 2

If its parallel it means that the slope will be the same

y = mx + b

-4 = -1/6 * (-6) + b

b = -5

Thus,

y = -1/6 x - 5

6 0
3 years ago
If f(x)=sinx 2x 1 and g is the inverse function of f
Bingel [31]

The value of the derivative of the function g(x) at x = 1 will be 1/3. Then the correct option is A.

<h3>What is an inverse function?</h3>

A function that may convert into another function is known as an inverse function or anti-function.

If the function is f(x) = sinx + 2x + 1.

Then the derivative of an inverse function g(x) of a function f(x) at a given value (a) will be

\rm g'(a) = \dfrac{1}{f'(g(a))}

The derivative of f(x) will be

f'(x) = cos x + 2

Then the given value of a will be

a = 1

g(x) = f⁻¹(x)

put x = 0, then we have

f(0) = sin 0 + 2(0) + 1

f(0) = 1

Put x = 1, in the function f⁻¹(x). Then we have

f⁻¹(1) = 0

and

g(1) = 0

Then put a = 1, then we have

\rm g'(a) = \dfrac{1}{f'(g(a))}\\\\g'(1) = \dfrac{1}{f'(g(1))}\\\\g'(1) = \dfrac{1}{f'(0)}\\\\g'(1) = \dfrac{1}{\cos 0 + 2}\\\\g'(1) = \dfrac{1}{1+2}= \dfrac{1}{3}

More about the inverse function link is given below.

brainly.com/question/2541698

#SPJ4

8 0
1 year ago
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