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rosijanka [135]
3 years ago
9

Which is the ratio formed when finding Tan M?

Mathematics
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

tanM = \frac{15}{8}

Step-by-step explanation:

tanM = \frac{opposite}{adjacent} = \frac{KL}{LM} = \frac{45}{24} = \frac{15}{8}

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4 years ago
It is known that x1 and x2 are roots of the equation 3x^2+2x+k=0, where 2x1=−3x2. Find k.
miss Akunina [59]

Answer:

k = 8

Step-by-step explanation:

Since the roots of the equation 3x² + 2x + k are x₁ and x₂ and 2x₁ = 3x₂.

By the roots of an equation, ax² + bx + c , where its roots are  x₁ and x₂. It follows that sum of roots are x₁ + x₂ = -b/a and product of roots are x₁x₂ = c/a.

Comparing both equations, a = 3 b = 2 and c = k.

So, x₁ + x₂ = -b/a = -2/3 and x₁x₂ = c/a = k/3

x₁ + x₂ = -2/3 and x₁x₂ = k/3

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Since 2x₁ = -3x₂, and -2x₁ = 3x₂substituting this into equations (1) and (2) above, we have

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3x₁ + (-2x₁) = -2  and x₁(3x₂) = k

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Substituting x₁ = -2 into -2x₁² = k, we have

-2x₁² = k

-2(-2)² = k

2(4) = k

8 = k

So, k = 8

7 0
3 years ago
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