What is the value of y that satisfies the equation below 5-y/2=9

2 answers:

7 0

5-y/2 = 9

First, we do the inverse operation and subtract 5 from both sides.

5 - y/2 = 9
-5 -5

-y/2 = 4

Now, we do the inverse operation ( multiply by the reciprocal)

-y/2 = 4
-y/2 * -2 = 4* -2
y= -8
y=-8

Now we have our final answer: y=-8

Check our work

5 - - 8/2= 9
5+4=9
9=9

OUR ANSWER IS CORRECT! :)

Evgesh-ka [11]3 years ago

7 0

If you would like to solve the equation 5 - y/2 = 9, you can calculate this using the following steps:

5 - y/2 = 9
5 - 9 = y/2
- 4 = y/2 /*2
y = - 4 * 2
y = - 8

The correct result would be - 8.

You might be interested in

In the upcoming election for governor, the most recent poll, based on 900 respondents, predicts that the incumbent will be reele

Paul [167]

Answer:

.0166

Step-by-step explanation:

Central Limit Theorem for proportions:

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $\sigma_{p} = \sqrt{\frac{p(1-p)}{n}}$

In this question:

$n = 900, p = 0.55$

What is σρˆ?

The standard deviation of the sample proportion, which is:

$\sigma_{p} = \sqrt{\frac{0.55*0.45}{900}} = 0.0166$

4 0

3 years ago

If x2+1/x2=18, find the value of x3−1/x3

Elden [556K]

Answer:

There are 2 answers : 76 or -76

Step-by-step explanation:

$x^2+\dfrac{1}{x^2} =18\\\\(x-\dfrac{1}{x} )^2=x^2+\dfrac{1}{x^2} -2=18-2=16\\\\x-\dfrac{1}{x}=4\ or\ x-\dfrac{1}{x}-4\\\\(x-\dfrac{1}{x} )^3=x^3-\dfrac{1}{x^3} -3x^2*\dfrac{1}{x}+3x*\dfrac{1}{x^2}\\\\=x^3-\dfrac{1}{x^3}-3(x-\dfrac{1}{x})\\\\x^3-\dfrac{1}{x^3}=(x-\dfrac{1}{x} )^3+3(x-\dfrac{1}{x})\\\\if\ x-\dfrac{1}{x}=4\ then \ x^3-\dfrac{1}{x^3}=4^3+3*4=64-12=76\\\\if\ x-\dfrac{1}{x}=-4\ then \ x^3-\dfrac{1}{x^3}=(-4)^3+3*(-4)=-64-12=-76\\\\$