Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
2n-4= n-10
-n. -n
n-4=-10
+4. +4
n=-6
Final answer: -6
Answer:
y = 3
Step-by-step explanation:
39 = 13y
y = 3 (explanation: by dividing 13)
Check answer:
39 = 13(3)
39 = 39
Answer:
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