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3 years ago

14

(-4, -7) and (-6, 9) in slope-intercept form. Show work

1 answer:

BigorU [14]3 years ago

5 0

Answer:

Equation of line in slope-intercept form is: y = -8x-39

Step-by-step explanation:

Given points are:

(-4, -7) and (-6, 9)

The slope-intercept form is given by the equation

$y = mx+b$

Here m is the slope of the line and b is the y-intercept.

m is found using the formula

$m = \frac{y_2-y_1}{x_2-x_1}$

Here

(x1,y1) = (-4-7)

(x2,y2) = (-6,9)

Putting the values in the formula

$m = \frac{9+7}{-6+4} = \frac{16}{-2} = -8$

Putting slope in general equation

$y = -8x+b$

Putting (-6,9) in the equation

$9 = -8(-6)+b\\9 = 48+b\\b = 9-48\\b = -39$

Putting the value of b we get

$y = -8x-39$

Hence,

Equation of line in slope-intercept form is: y = -8x-39

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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If we know that $K = (2, 0)$ , $K' = (1, 0)$ , $T = (3, 0)$ , $T' = (1.5,0)$ , $P = (1, 5)$ , $P' = (0.5, 2.5)$ , $J = (0, 3)$ and $J' = (0, 1.5)$ , then the coefficients are, respectively:

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