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ipn [44]
3 years ago
10

A multiple choice test consists of six questions, each of which has four choices. Each question has exactly one correct answer.

Mathematics
1 answer:
mario62 [17]3 years ago
6 0
To get 4 or fewer correct, at least 2 answers have to be wrong. And the probability of that is:
3/4 x 3/4=9/16
1-9/16=probability that 4 or fewer are correct=7/16 ☺☺☺☺
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The profits in hundreds of dollars, P(c), that a company can make from a product is modeled by a function of the price, c, they
Valentin [98]

Answer:

6400

Step-by-step explanation:

Given the profit function ;

P(c) = –20c2 + 320c + 5,120

The maximum value is given by :

f(h) ; where, h = - b /2a

From P(C) ; a = - 20 ; b = 320

h = - b / 2a = - 320 / 2(-20) = - 320 / 40 = 8

c = h

P(8) = –20(8)² + 320(8) + 5,120

P(8) = - 1280 + 2560 + 5120

= 6400

4 0
3 years ago
What are the coordinates for a dilated triangle, A’B’C’, if the scale factor for the dilation is 0.75?
ycow [4]

Answer:

D.

A’(–3.75, 0.75); B’(0, 1.5); C’(3, –1.5)

Step-by-step explanation:

Did this on edgenut and got it right

Hope this helps

6 0
2 years ago
Read 2 more answers
5x-8=2x+25 help help
Maurinko [17]
The answer would be x=11
7 0
2 years ago
You are randomly selecting 3 cans of regular and diet cola, but assume that there are 6 cans of regular cola and 7 cans of diet
gayaneshka [121]

Answer:0.367

Step-by-step explanation:

Given

There are 6 cans of regular and 7 cans of diet cola

number of ways of selecting 2 regular colas and 1 can of diet cola is

\Rightarrow ^6C_2\times ^7C_1

The total no of ways of selecting 3 items out of 13 items is

\Rightarrow ^{13}C_3

Probability is

\Rightarrow P=\dfrac{^6C_2\times ^7C_1}{^{13}C_3}=\dfrac{105}{286}\\\Rightarrow P=0.367

6 0
2 years ago
Find the 6th term of the geometric sequence, given the first term and common ratio a1= 5 and r=3/2
uysha [10]

<u>Answer</u>



37.96875



<u>Explanation</u>

In geometric sequence we use the formula below to find the nth of a sequence.


Tn = ar⁽ⁿ⁻¹⁾

Where a ⇒ first term

n ⇒ the term we are looking for

T₆ = 5 × (3/2)⁶⁻¹

= 5 × (3/2)⁵

= 5 × 243/32

= 1215/32

= 37 31/32

= 37.96875

6 0
3 years ago
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