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katovenus [111]
3 years ago
7

The graph shows a parabola and its focus. Write the equation of the parabola in vertex form.​

Mathematics
1 answer:
finlep [7]3 years ago
7 0

9514 1404 393

Answer:

  y = -1/12x² +2

Step-by-step explanation:

For vertex (h, k) and vertex-to-focus distance p, the vertex form equation is ...

  y=\dfrac{1}{4p}(x-h)^2+k

Here, the vertex-to-focus distance is -1-2 = -3 units. The vertex is (h, k) = (0, 2). So, the equation of the parabola is ...

  \boxed{y=-\dfrac{1}{12}x^2+2}

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*URGENT*<br> I don’t understand this and i don’t know the answers, please help!!
motikmotik

Answer:

A) x>8

B) x<4

Step-by-step explanation:

A) 3x+5>29

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a line has a slope of -2 and includes the points (-1,r) and (2,4). write the value of r in the empty box
guajiro [1.7K]

Answer:

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Step-by-step explanation:

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3 years ago
11. What is the y-intercept of a line that passes through the point (5,17)
Viefleur [7K]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • y - intercept = -3

\textsf{  \underline{\underline{Steps to solve the problem} }:}

Equation of straight line in point - slope form :

\qquad❖ \:  \sf \:y - y1 = m(x - x1)

( m = slope = 4, point (5 , 17) )

\qquad◈  \:  \:  \sf \: y - 17 = 4(x - 5)

\qquad◈  \:  \:  \sf \: y  - 17= 4x - 20

\qquad◈  \:  \:  \sf \: y = 4x - 20 + 17

\qquad◈  \:  \:  \sf \: y = 4x - 3

Now, it's the form of line in slope - intercept form, ( slope = coefficient of x = 4 and y - intercept = -3 )

\qquad \large \sf {Conclusion}  :

\qquad◈  \:  \:  \sf \: y \:  \: int =  - 3

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Answer: 3-t
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Read 2 more answers
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