Answer:
a. 2^6, or 64 opcodes.
b. 2^5, or 32 registers.
c. 2^16, or 0 to 65536.
d. -32768 to 32768.
Explanation:
a. Following that the opcode is 6 bits, it is generally known that the maximum number of opcodes should be 2^6, or 64 opcodes.
b. Now, since the size of the register field is 5 bits, we know that 2^5 registers can be accessed, or 32 registers.
c. Unsigned immediate operand applies to the plus/minus sign of the number. Since unsigned numbers are always positive, the range is from 0 to 2^16, or 0 to 65536.
d. Considering that the signed operands can be negative, they need a 16'th bit for the sign and 15 bits for the number. This means there are 2 * (2^15) numbers, or 2^16. However, the numbers range from -32768 to 32768.
Def_pow_(self,b): if not then I’m sorry
Answer:
(1) Protecting the privacy of personal data and proprietary information
(2) Proprietary Information
These two cannot be infringed on but below are the policies that must be taken in high esteem and can be infringed upon
(1) Disaster Recovery Policy
(2) Acceptable Use Policy
(3) Business Continuity plan
Answer:
d) daco = new Banana;
Explanation:
Dynamically allocated variables have their memory allocated in the heap memory.We declare a dynamical variable like this:-
int *a=new int ;
It means a pointer a is created on the stack memory which hold the address of the block that hold the value of variable a in heap memory.
We already have the pointer daco. We just have to initialize with keyword new.
It will be like daco=new Banana; which matches the option d.
The atomic number for Neon is 10.
I do not see the info for the second part of the question
