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Crank
3 years ago
10

What is the equation of the line

Mathematics
2 answers:
Eva8 [605]3 years ago
7 0
Y=2x+2 because it is starting by 2 on the Y and keeps goin up by two
balandron [24]3 years ago
6 0

Answer:

y=2x+2

Step-by-step explanation:

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Write the standard equation of the circle with the given center and passes through the given point. Center (7,-2); Point= (1,-6)
vodomira [7]

Answer:

(x - 7)² + (y + 2)² = (2√13)²

Step-by-step explanation:

We already know that the center is at (7, -2), but must find the radius.  The radius is the distance between the points (7, -2) and (1, -6):

r = √ [6² + 4²] ) = √(36 + 16) = √52 = √4√13 = 2√13.

Then the desired equation is (x - 7)² + (y + 2)² = (2√13)²

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2 years ago
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grandymaker [24]

423 \times 10 {}^{2}

2 \times 10 {}^{3}

92 \times 10 {}^{5}

4 \times 10 {}^{3}

80 \times 10 {}^{6}  = 8 \times 10 {}^{7}

32 \times 10 {}^{9}

4 0
2 years ago
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Choose the correct simplification of the expression (8x − 5)(2x2 − 5x − 6). (1 point)
OleMash [197]
The easiest terms to check are the first (8x)(2x²) = 16x³ and the last (-5)(-6) = 30. This check eliminates the first choice. The remaining choices differ only in the sign and coefficient of the squared term, so that is the one we need to find.

The squared term will be the sum of the products of factors whose degrees total 2:
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The appropriate choice is
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6 0
2 years ago
Solve the quadratic equation by completing the square x^2+5x-3=0
PIT_PIT [208]

{\tt{x =  \frac{ -b± \sqrt{ {b}^{2} - 4ac } }{2a} }}

{\tt{ x =  \frac{ - 5±\sqrt{{5}^{2}  - 4 \times 1 \times ( - 3)} }{2 \times 1} }}

{\tt{x =  \frac{ - 5±\sqrt{25 + 12} }{2} }}

{\tt{x =  \frac{ - 5 ±\sqrt{37}  }{2} }}

\:  \:

{\tt{x =  \frac{ - 5 +  \sqrt{37} }{2} }}

{\tt{x =  \frac{ - 5 -  \sqrt{37} }{2} }}

8 0
2 years ago
What is the x-intercept of the line with this equation 13x+y=−15 ? Enter your answer in the box. ( , 0)
Nastasia [14]

Answer:  The required x-intercept of the given line is \left(-\dfrac{15}{13},0\right).

Step-by-step explanation:  We are given to find the x-intercept of the line with the following equation :

13x+y=-15~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We know that

x-intercept of a line is a point on the line where the line crosses the x-axis, that is y co-ordinate is 0.

Substituting y = 0 in equation (i), we get

13x+y=--15\\\\\Rightarrow 13x+0=-15\\\\\Rightarrow 13x=-15\\\\\Rightarrow x=-\dfrac{15}{13}.

Thus, the required x-intercept of the given line is \left(-\dfrac{15}{13},0\right).

4 0
3 years ago
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