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ladessa [460]
3 years ago
13

The sum of two factors of 48 is nineteen. the larger factor, x, is one more than five times the smaller factor, y. which system

of equations can be used to find the numbers
a. x = 19 - y
x = 5y +1
b. x = 19 + y
y = 5x + 1
c. x = y + 19
y = 5x -1
d. x = y - 19
x = 5y +1
Mathematics
2 answers:
Dominik [7]3 years ago
7 0
Hmm b x=19 I think this because it is more than 5 times
Ymorist [56]3 years ago
5 0
Umm b. X = 19 + y I think because it has a add
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2 years ago
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olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

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y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

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