F(2a)=35
f(2a)=(2a)^2-1=35
(2a)^2-1=35
add 1 both sides
(2a)^2=36
sqrt both sides
2a=+/-6
divde 2
a=+/-3
a=3 or -3
Answer:
s = 16.2 units
Step-by-step explanation:
s^2 = 15^2 + 6^2 (6 is 1/2 of 12)
s^2 = 225 + 36
s^2 = 261
s = 16.16
16 large candles and 12 small candles were sold.
Step-by-step explanation:
Given,
Worth of candles sold = $144
Total candles sold = 28
Cost of each large candle = $6
Cost of each small candle = $4
Let,
x be the number of large candles sold.
y be the number of small candles sold.
According to given statement;
x+y=28 Eqn 1
6x+4y=144 Eqn 2
Multiplying Eqn 1 by 4
![4(x+y=28)\\4x+4y=112\ \ \ Eqn\ 3](https://tex.z-dn.net/?f=4%28x%2By%3D28%29%5C%5C4x%2B4y%3D112%5C%20%5C%20%5C%20Eqn%5C%203)
Subtracting Eqn 3 from Eqn 2
![(6x+4y)-(4x+4y)=144-112\\6x+4y-4x-4y=32\\2x=32](https://tex.z-dn.net/?f=%286x%2B4y%29-%284x%2B4y%29%3D144-112%5C%5C6x%2B4y-4x-4y%3D32%5C%5C2x%3D32)
Dividing both sides by 2
![\frac{2x}{2}=\frac{32}{2}\\x=16](https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7B2%7D%3D%5Cfrac%7B32%7D%7B2%7D%5C%5Cx%3D16)
Putting x=16 in Eqn 1
![16+y=28\\y=28-16\\y=12](https://tex.z-dn.net/?f=16%2By%3D28%5C%5Cy%3D28-16%5C%5Cy%3D12)
16 large candles and 12 small candles were sold.
Keywords: linear equation, subtraction
Learn more about linear equations at:
#LearnwithBrainly
Answer:
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Step-by-step explanation: