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Vitek1552 [10]
3 years ago
6

Find mGM if KP = PL and GH = 36 ft.​

Mathematics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

arc GM = 77°

Step-by-step explanation:

full circle = 360°

arc GMH = arc GNJ, so:

arc GMH = (360°- 52°)/2 = 154°

because line MP is perpendicular to line GH, arc GM = arc MH

arc GM = 154°/2 = 77°

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61.7 is what percent of 64? Round to the nearest thousandth.
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Answer:

96.406%

Step-by-step explanation:

(61.7 ÷ 64) x 100 = 96.40625 = 96.406% (nearest hundredth)

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2 years ago
What type of angles are 4 and 5
vodomira [7]

Answer:

option c. Alternate interior angles

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What is the answer I really need help
katrin2010 [14]

Answer:

44.6

Step-by-step explanation:

Since the sides with the two tick marks are equal to 7.4, and there are three of these sides, they are equal to 7.4 times 3, which is 22.2. The remaining sides have 1 tick, meaning they are 11.2, meaning this is 11.2 * 2, which is 22.4. The combined perimeter is 44.6 cm.

7 0
3 years ago
The vertex of this parabola is at (-4, -1). When the y-value is 0, the x-value is 2. What is the coefficient of the squared term
satela [25.4K]
\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
y=a(x-(-4))^2-1\implies y=a(x+4)^2-1
\\\\\\
\textit{now, we also know that }
\begin{cases}
y=0\\
x=2
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3 years ago
Problem PageQuestion Working together, two pumps can drain a certain pool in hours. If it takes the older pump hours to drain th
gizmo_the_mogwai [7]

Answer:

10.5 hours.

Step-by-step explanation:

Please consider the complete question.

Working together, two pumps can drain a certain pool in  6  hours. If it takes the older pump  14  hours to drain the pool by itself, how long will it take the newer pump to drain the pool on its own?

Let t represent time taken by newer pump in hours to drain the pool on its own.

So part of pool drained by newer pump in one hour would be \frac{1}{t}.

We have been given that it takes the older pump 14 hours to drain the pool by itself, so part of pool drained by older pump in one hour would be \frac{1}{14}.

Part of pool drained by both pumps working together in one hour would be \frac{1}{6}.

Now, we will equate the sum of part of pool emptied by both pumps with  \frac{1}{6} and solve for t as:

\frac{1}{14}+\frac{1}{t}=\frac{1}{6}

\frac{1}{14}\times 42t+\frac{1}{t}\times 42t=\frac{1}{6}\times 42t

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t=10.5

Therefore, it will take 10.5 hours for the newer pump to drain the pool on its own.

6 0
2 years ago
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