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2 years ago

Solve using any method 4x-y=20 and -2x-2y=10

Mathematics

2 answers:

dsp732 years ago

7 0

Answer:

if you're trying to find the slope, it is (3, -8) were you looking for the slope?

Step-by-step explanation:

i hope this helps, have a great day:)

Ivahew [28]2 years ago

7 0

Answer: the answer is x =3, y = -8

Step-by-step explanation:

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Find a formula for the sum of the first n even positive integers.

melisa1 [442]

So even postive integers are by defention in form 2k where k is a natural number so
let the sum of even integers to n=S
S=2(1+2+3+4+5+6+7+8+......+k-1+k
divide bith sides of equation 1 by 2
0.5S=1+2+3+4+5+...........+k-1+k
S=2(k+(k-1)+..............................+2+1)
divide both sides of equation 2 by 2
0.5S=k+k-1+..............................+2+1)
by adding both we will get
___________________________
S=(k+1)(k)
so the sum will be equal to
S=
${k}^{2} + k$
so let us test the equation
for the first 3 even number there sums will be
2+4+6=12
by our equation 3^2+3=12
gave us the same answer so our equation is correct

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2 years ago

How do you fine out if y is a linear function of x on a graph

mote1985 [20]

Answer: If a vertical line can be drawn to touch the graph of a function in more than one place, then is NOT a function of . If it is not possible to draw a vertical line to touch the graph of a function in more than one place, then y is a function of x.

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2 years ago

Find the x in the following triangle <br> I’ll give brainliest

densk [106]

Answer:

Step-by-step explanation:

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1 year ago

Find the slope of the line passing through the points (6, -6) and (4, -4)

djyliett [7]

To find the slope (m), use the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$ and plug in the two points

(4, -4) = (x₁, y₁)

(6, -6) = (x₂, y₂)

[lines usually go from left to right, so the point furthest to the left is the 1st point]

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-6-(-4)}{6-4}$ [two negative signs cancel each other out and become positive]

$m=\frac{-6+4}{6-4}$

$m=\frac{-2}{2}$

m = -1

3 0

2 years ago

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

7 0

2 years ago