Answer:
For less than 7 uniforms.
Step-by-step explanation:
The first company she called charges $70 per uniform.
So, the cost of x uniforms will be $70x.
The second company she called charges $280 plus $30 per uniform.
So, the cost of x uniform will be $(280 + 30x).
Now, if the total cost of purchasing x number of uniforms from the first company is less than that from the second company then, we can write the inequality equation as
70x < 280 + 30x
⇒ 70x - 30x < 280
⇒ 40x < 280
⇒ x < 7
Therefore, for less than 7 uniforms the cost from the first company will be less than the cost from the second company. (Answer)
Answer:
142.92
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
1 step:
n=1, then
So, for j=1 this statement is true
2 step:
Assume that for n=k the following statement is true
3 step:
Check for n=k+1 whether the statement
is true.
Start with the left side:
According to the 2nd step,
Substitute it into the 
So, you have proved the initial statement
Answer:
=3–√−13–√+1⋅3–√−13–√−1
=(3–√−1)23–√2−12
=3–√2+12−23–√3−1
=4−23–√2
2−13–√
a=2,b=−1.
Step-by-step explanation:
Answer:
one solution at x=1,y=4 point
