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stich3 [128]
3 years ago
6

What is the approximate volume of a cone with a radius of 15 cm and a height of 4 cm? Round your answer to the nearest hundredth

and include units
Mathematics
1 answer:
vichka [17]3 years ago
6 0

Answer:

Volume of a cone =942.86cm^3

Step-by-step explanation:

Given that the radius of a cone is 15cm and its height is 4cm

That is r=15cm and h=4cm

To find the volume of a cone :

volume of a cone=\frac{\pi r^2h}{3} cubic units

Now substitute the values in the formula we get

volume of a cone=\frac{(\frac{22}{7}) (15)^2(4)}{3}  

=\frac{(\frac{22}{7}) (225)(4)}{3}

=\frac{19800}{21}

=942.857

Now round to nearest hundredth

=942.86

Therefore Volume of a cone=942.86cm^3

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A man bought A $250 suit and four shirts for $398 how much did she spend per shirt
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Answer: 99.5

Step-by-step explanation:

398 ÷ 4


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A coin is tossed, and a die is rolled. Find the probability of getting heads and then rolling a 6.
Colt1911 [192]

Answer:

1/2 and 1/6

Step-by-step explanation:

8 0
3 years ago
Find the volume of the cone.
Alona [7]

answer:

2,558

step-by-step explanation:

the formula for the volume of a cone is v=πr²h/3

with that let us 'fill in' the formula-

v=π*9.6²*26.5/3

v=2,557.51

then since you've asked us to round the answer to the nearest whole number that would be 2,558

good luck :)

i hope this helps

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5 0
3 years ago
Mary and Jeff both have jobs at a baseball stadium selling bags of peanuts. They each get paid $12 per game
Anarel [89]
A) 1.75p + 12 = 54
1.75p = 42
p = 24 bags

b) 1.75(70) + 12 = b
122.5 + 12 = b
b = $134.50
6 0
3 years ago
The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i
kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

S=\pi r\sqrt{r^2+h^2}

and volume,

V=\frac{1}{3}\pi r^2 h

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

f(r,h)=\frac{1}{3}\pi r^2 h

subject to,

g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)

We know for maximum volume r\neq 0. So let \lambda be the Lagranges multipliers be such that,

f_r=\lambda g_r

\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)

And,

f_h=\lambda g_h

\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}

\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)

Substitute (3) in (2) we get,

\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)

\implies h^2=2r^2

Substitute this value in (1) we get,

\pi r\sqrt{h^2+r^2}=8

\implies \pi r \sqrt{2r^2+r^2}=8

\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252

Then,

h=\sqrt{2}(1.21252)\equiv 1.71476

Hence largest volume,

V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114

3 0
3 years ago
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