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2 years ago

6

What is the approximate volume of a cone with a radius of 15 cm and a height of 4 cm? Round your answer to the nearest hundredth

and include units

1 answer:

vichka [17]2 years ago

6 0

Answer:

Volume of a cone $=942.86cm^3$

Step-by-step explanation:

Given that the radius of a cone is 15cm and its height is 4cm

That is r=15cm and h=4cm

To find the volume of a cone :

volume of a cone $=\frac{\pi r^2h}{3}$ cubic units

Now substitute the values in the formula we get

volume of a cone $=\frac{(\frac{22}{7}) (15)^2(4)}{3}$

$=\frac{(\frac{22}{7}) (225)(4)}{3}$

$=\frac{19800}{21}$

$=942.857$

Now round to nearest hundredth

$=942.86$

Therefore Volume of a cone $=942.86cm^3$

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Answer: 34.54feet

Step-by-step explanation:

Thw circumference of the pool will be calculated by using the formula:

= 2πr

where

π = 3.14

r = 5.5

Therefore, circumference = 2πr

= 2 × 3.14 × 5.5

= 34.54feet

Therefore, the circumference of the pool to the nearest hundredth is 34.54feet.

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2 years ago

Suppose there are two circles where the radius of one circle is twice the radius of the other circle. Each circle has an arc whe

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Answer:

$L=2l$ where $l,L$ denote arc lengths of two circles

Step-by-step explanation:

Let $l,L$ denote arc lengths of two circles, $r,R$ denote corresponding radii and

$\alpha _1\,,\alpha _2$ denote the corresponding central angles.

So,

$l=r\alpha _1$ and $L=R\alpha _2$

This implies $\alpha _1=\frac{l}{r}$ and $\alpha _2=\frac{L}{R}$

As each circle has an arc where the measures of the corresponding central angles are the same, $\alpha _1=\alpha _2$

$\frac{l}{r}=\frac{L}{R}$

As radius of one circle is twice the radius of the other circle,

$R=2r$

$\frac{l}{r}=\frac{L}{2r}\\\frac{l}{1} =\frac{L}{2}\\L=2l$

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2 years ago

POSSIBLE POINTS. 1

erastova [34]

Answer:

Step-by-step explanation:

a^2 + b^2 = c^2

where

a and b are the legs

and

c is the hypotenuse

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a^2 + b^2 = c^2

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8 months ago

To test the belief that sons are taller than their fathers, a student randomly selects 13 fathers who have adult male children.

KATRIN_1 [288]

Answer:

1) B. The differences are normally distributed or the sample size is large

C. The sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀: $\bar x_1$ = $\bar x_2$

The alternative hypothesis Hₐ: $\bar x_1$ < $\bar x_2$

Test statistic, t = -0.00693

p- value = 0.498

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers at 0.10 level of significance

Step-by-step explanation:

1) B. The differences are normally distributed or the sample size is large

C. The sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀: $\bar x_1$ = $\bar x_2$

The alternative hypothesis Hₐ: $\bar x_1$ < $\bar x_2$

The test statistic for t test is;

$t=\dfrac{(\bar{x}_1-\bar{x}_2)}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}$

The mean

Height of Father, h₁, Height of Son h₂

72.4, 77.5

70.6, 74.1

73.1, 75.6

69.9, 71.7

69.4, 70.5

69.4, 69.9

68.1, 68.2

68.9, 68.2

70.5, 69.3

69.4, 67.7

69.5, 67

67.2, 63.7

70.4, 65.5

$\bar x_1$ = 69.6

s₁ = 1.58

$\bar x_2$ = 69.9

s₂ = 3.97

n₁ = 13

n₂ = 13

$t=\dfrac{(69.908-69.915)}{\sqrt{\dfrac{3.97^{2}}{13}-\dfrac{1.58^{2} }{13}}}$

(We reversed the values in the square root of the denominator therefore, the sign reversal)

t = -0.00693

p- value = 0.498 by graphing calculator function

P-value > α Therefore, we do not reject the null hypothesis

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers at 0.10 lvel of significance

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3 years ago

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shutvik [7]

Answer:

I agree with your answer C!!

Step-by-step explanation:

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