All categories

3 years ago

Can someone tell me if this is correct and if not tell me how to put it plzzzzzzzz

Mathematics

1 answer:

andrezito [222]3 years ago

6 0

What do you want to check? The graph?

You might be interested in

Type SSS, SAS, ASA, SAA, or HL To justify why the two larger triangles are Congruent.

lakkis [162]

I’m assuming the answer is HL since they only gave us two letters.

6 0

3 years ago

What is the word form of 3.75

Anna [14]

The given number is 3.75, we will read the number separately first as follows:
before the decimal point we have 1 3 which is read as three
after the decimal point we have a .75 which is read as seventy-five hundredth

So, combing the two parts, we can find that the word form of 3.75 is:
three and seventy-five hundredth.

6 0

4 years ago

Read 2 more answers

Point P'P

Snowcat [4.5K]

Given:

The point P' is the image of the point P under the translation $(x,y) \implies (x-6, y-1)$

The coordinates of the point P are (6,0)

We need to determine the coordinates of the point P'

Coordinates of the point P':

The coordinates of the point P' can be determined by substituting the coordinates of the point P(6,0) in the translation.

Thus, substituting the coordinates, we have;

$(6,0)\implies (6-6,0-1)$

Simplifying the coordinates, we get;

$(6,0)\implies (0,-1)$

Thus, the coordinates of the point P' is (0,-1)

5 0

3 years ago

You spend $55 on sneakers, receive $30 for

Pavel [41]

Answer:

$149

Step-by-step explanation:

He spent 55 on sneakers at first, then he recieved 30 more, and gave 20 to the mom, which i added to the equation, and what he has left i also added.

4 0

3 years ago

Log(x⁴+3x³) - log(X + 3 ) + log2 - log6 = 2logx . find the value of x

AfilCa [17]

The given equation is

$\begin{gathered} \log (x^4+3x^3)-\log (x+3)+\log 2-\log 6=2\log x \\ \log (\frac{x^4+3x^{3^{}}}{x+3})+\log \frac{2}{6}=\log x^2 \\ \log \frac{x^3(x+3)}{x+3}+\log \frac{1}{3}=\log x^2 \\ \log x^3+\log \frac{1}{3}=\log x^2 \\ \log \frac{x^3}{3}=\log x^2 \\ \frac{x^3}{3}=x^2 \\ x^3-3x^2=0 \\ x^2(x-3)=0 \end{gathered}$

hence

$x=0\text{ or x=3}$

But x cannot be zero so x=3

So the value of x is 3

7 0

1 year ago